如何使用详细信息披露按钮与故事板?

时间:2012-06-27 20:30:01

标签: ios xcode storyboard segue disclosure

我尝试将详细信息披露按钮与故事板一起使用,但是当我从Disclosure Button构建一个segue到一个新视图时,它只能按下表格单元格,而不是当我按下详细信息披露按钮时。

我该怎么办?

谢谢,

哈德

2 个答案:

答案 0 :(得分:5)

我可能错了,但我发现它需要通过UITableDelegate代码实现:

#pragma mark - Table view delegate methods

- (void)tableView:(UITableView *)tableView accessoryButtonTappedForRowWithIndexPath:(NSIndexPath *)indexPath
{
    // do a segue based on the indexPath or do any setup later in prepareForSegue
    [self performSegueWithIdentifier:@"segueName" sender:self];
}

然后在prepareForSegue

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{

    if([segue.identifier isEqualToString:@"segueName"]){

        NSIndexPath * indexPath =  self.sequenceTableView.indexPathForSelectedRow;
       // do some prep based on indexPath, if needed

     }
}

答案 1 :(得分:0)

skinnyTOD的答案很好。但我不知道为什么self.sequenceTableView.indexPathForSelectedRow;返回nil(0x0000000),我必须使用一个属性来保存selectedButtonTappedForRowWithIndexPath中的selectedRow:

- (void)tableView:(UITableView *)tableView accessoryButtonTappedForRowWithIndexPath:(NSIndexPath *)indexPath {
    // do a segue based on the indexPath or do any setup later in prepareForSegue
    self.selectedRow = indexPath.row;
    [self performSegueWithIdentifier:@"segueName" sender:self];
}

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
    if ([segue.identifier isEqualToString:@"segueName"]) {
        // use self.selectedRow here
    }
}