我正在尝试使用php格式化我的数据库中的一些html输出,这是我的问题:
应如何格式化:
...
<li>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-1</div>
<div class="some-class-1">ARRAY-ELEMENT-2</div>
<div class="some-class-1">ARRAY-ELEMENT-3</div>
<div class="some-class-2">ARRAY-ELEMENT-4</div>
</div>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-5</div>
<div class="some-class-1">ARRAY-ELEMENT-6</div>
<div class="some-class-1">ARRAY-ELEMENT-7</div>
<div class="some-class-2">ARRAY-ELEMENT-8</div>
</div>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-9</div>
<div class="some-class-1">ARRAY-ELEMENT-10</div>
<div class="some-class-1">ARRAY-ELEMENT-11</div>
<div class="some-class-2">ARRAY-ELEMENT-12</div>
</div>
</li>
<li>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-13</div>
<div class="some-class-1">ARRAY-ELEMENT-14</div>
<div class="some-class-1">ARRAY-ELEMENT-15</div>
<div class="some-class-2">ARRAY-ELEMENT-16</div>
</div>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-17</div>
<div class="some-class-1">ARRAY-ELEMENT-18</div>
<div class="some-class-1">ARRAY-ELEMENT-19</div>
<div class="some-class-2">ARRAY-ELEMENT-20</div>
</div>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-21</div>
<div class="some-class-1">ARRAY-ELEMENT-22</div>
<div class="some-class-1">ARRAY-ELEMENT-23</div>
<div class="some-class-2">ARRAY-ELEMENT-24</div>
</div>
</li>
... etc.
数据保存在从mysql db收集的数组中,到目前为止我已经达到了这个目的:
$num_thumbs = 4; //Number od elemets in a row
$result = myQueryFunction("SELECT * FROM table_name ORDER BY Id ASC");
$num_rows = mysql_num_rows($result);
if (!empty($num_rows)) {
while ($row = mysql_fetch_array($result)) {
$thumbs_array[] = "<a href=\"" . $row[0] . "\"><img src=\"" . $row[1] . "\"";
}
$thumb_p = "<div>\n";
mysql_free_result($result);
$i = 1;
foreach ($thumbs_array as &$thumb_link) {
if ($i == $num_thumbs) {
$i = 1;
$thumb_p .= "<div class=\"some-class-2\">" . $thumb_link . "</div>";
$thumb_p .= "</div>\n<div class=\"row-wrapper\">\n";
} else {
$thumb_p .= "\t\n<div class=\"some-class-1\">" . $thumb_link . "</div>";
$i++;
}
}
$thumb_p .= "\n</div>\n";
}
print($thumb_p);
这仅涵盖代码格式的这一部分:
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-13</div>
<div class="some-class-1">ARRAY-ELEMENT-14</div>
<div class="some-class-1">ARRAY-ELEMENT-15</div>
<div class="some-class-2">ARRAY-ELEMENT-16</div>
</div>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-17</div>
<div class="some-class-1">ARRAY-ELEMENT-18</div>
<div class="some-class-1">ARRAY-ELEMENT-19</div>
<div class="some-class-2">ARRAY-ELEMENT-20</div>
</div>
<div class="row-wrapper">
<div class="some-class-1">ARRAY-ELEMENT-21</div>
<div class="some-class-1">ARRAY-ELEMENT-22</div>
<div class="some-class-1">ARRAY-ELEMENT-23</div>
<div class="some-class-2">ARRAY-ELEMENT-24</div>
</div>
我一直在考虑使用一些变量$ newList = null;这将在每一行更新,所以我可以检查它是否已经改变了下一行。 有任何想法吗?在此先感谢:)
答案 0 :(得分:0)
看来你正试图每三个div放一个li。在这种情况下,您可以这样做:
$thumb_p = "<li>\n<div class=\"row-wrapper\">\n";
mysql_free_result($result);
$i = 1;
$j = 0;
foreach ($thumbs_array as &$thumb_link) {
if ($i == $num_thumbs) {
$i = 1;
$thumb_p .= "<div class=\"some-class-2\">" . $thumb_link . "</div>";
$thumb_p .= "</div>\n";
if($j == 3)
{
$thumb_p .= "</li>\n<li>";
$j = 0;
}
$thumb_p .= "<div class=\"row-wrapper\">\n";
$j++;
} else {
$thumb_p .= "\t\n<div class=\"some-class-1\">" . $thumb_link . "</div>";
$i++;
}
}
$thumb_p .= "\n</div>\n</li>\n";
我实际上无法尝试,但我认为没关系。每三个行打包器就会添加一个li。