Question

我有以下数组。它包含昵称和名称：

$nickAndNames = array( 
    array( "Johnie", "John Larson" ),
    array ("Maggie", "Margaret London" ),
    array("Nic","Nicholas Carradine")
);

你能帮我打印出第一个元素吗？我的意思是Johnie，Maggie，Nic。

Answer 1

数组的每个元素都是另一个数组。该内部数组的每个元素又包含2个元素：元素0（字符串，昵称）和元素1（另一个字符串，名称）。因此，您首先需要遍历$nicksAndNames数组，然后显示内部数组的第一个元素（即元素0）：

// loop through $nickAndNames and assign, in turn, each inner array
// to a variable named $nickAndName
foreach ($nickAndNames as $nickAndName) {
    // this $nickAndName variable now contains the inner array, something like:
    // array("Johnie", "John Larson"), so "Johnie" is the first element,
    // element 0
    echo $nickAndName[0];
}

Answer 2

您希望使用foreach循环遍历数组，然后打印第一个元素index 0。

$nickAndNames = array( 
    array( "Johnie", "John Larson" ),
    array ("Maggie", "Margaret London" ),
    array("Nic","Nicholas Carradine")
);

foreach ($nickAndNames as $name) {
    echo $name[0];
}

Answer 3

这将遍历所有名称：

foreach( $nickAndNames as $data)
    echo $data[0];

Answer 4

看这里：

foreach ($nickAndNames as $key => $value) {
    var_dump($value[0]);
}

Answer 5

这应该给你一些工作：

foreach ($nickAndNames as $person)
{
    reset($person); // May not be needed.
    print current($person);
}

Answer 6

如果你可以使用如下所示的正确命名的键值对来纠正你的数组，

$nickAndNames = array( 
         array( "nickname" => "Johnie", "name" => "John Larson" ),
         array ("nickname" => "Maggie", "name" => "Margaret London" ),
         array("nickname" => "Nic","name" => "Nicholas Carradine")
         );

你可以做到

foreach($nickAndNames as $nickAndName){
    if(is_array($nickAndName))
    {
        foreach($nickAndName as $nN)
        {
             echo 'nickname = '. $nN['nickname'];
             echo 'name = '. $nN['name'];
        }
    }
    else
    {
        echo 'nickname = '. $nN['nickname'];
        echo 'name = '. $nN['name'];
    }
}

希望这有帮助，

KARTHIK

麻烦在PHP中循环多维数组

6 个答案: