Question

我有一个php文件，用于检查用户数据库的登录名和密码，它运行正常。

但是如果用户不存在或用户输入的密码不正确并且错误后返回上一页，我无法验证显示的确切错误，请帮助我显示这些错误。

<?php // access.php
include_once 'common.php';
include_once 'db.php';

session_start();

$uid = isset($_POST['uid']) ? $_POST['uid'] : $_SESSION['uid'];
$pwd = isset($_POST['pwd']) ? $_POST['pwd'] : $_SESSION['pwd'];

if(!isset($uid)) {
  ?>

  <!DOCTYPE html PUBLIC "-//W3C/DTD XHTML 1.0 Transitional//EN" 
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
  <html xmlns="http://www.w3.org/1999/xhtml">
  <head>
<title>Login</title>
    <meta http-equiv="Content-Type"
      content="text/html; charset=iso-8859-1" />
<head>
<style type="text/css">
<!--
.style1 {
    font-size: 16px;
    font-family: Verdana, Arial, Helvetica, sans-serif;
}
.style3 {
    font-size: 12px;
    font-family: Verdana, Arial, Helvetica, sans-serif;
}
-->
</style>

  </head>
<body>
  <h1 class="style1"> <br><br>  Login Required </h1>
  <span class="style3"><br>
  You <strong>must login to access this area </strong>of the site. <br>
  <br>
  If you are not a registered user, please contact your Admin
     to sign up for instant access!</span>
  <p><form method="post" action="<?=$_SERVER['PHP_SELF']?>">
    <span class="style3">User ID:&nbsp;&nbsp;&nbsp;&nbsp;    
    <input type="text" name="uid" size="12" />
    <br>
    <br />
    Password:</span>    
    <input type="password" name="pwd" SIZE="12" />
    <br>
    <br />
    <input type="submit" value="Login" />
  </form></p>
</body>
 </html>

  <?php
  exit;
}

$_SESSION['uid'] = $uid;
$_SESSION['pwd'] = $pwd;

dbConnect("svga");
$sql = "SELECT * FROM user WHERE
        userid = '$uid' AND password = '$pwd'";
$result = mysql_query($sql);
if (!$result) {
  error('A database error occurred while checking your '.
        'login details.\\nIf this error persists, please '.
        'contact you@example.com.');
   }

if (mysql_num_rows($result) == 0) {
  unset($_SESSION['uid']);
  unset($_SESSION['pwd']);
  ?>

  <!DOCTYPE html PUBLIC "-//W3C/DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
  <html xmlns="http://www.w3.org/1999/xhtml">
      <head>
    <title> Access Denied </title>
    <meta http-equiv="Content-Type"
      content="text/html; charset=iso-8859-1" />
        <style type="text/css">
<!--
.style1 {
    font-size: 16px;
    font-family: Verdana, Arial, Helvetica, sans-serif;
}
.style3 {
    font-size: 12px;
    font-family: Verdana, Arial, Helvetica, sans-serif;
}
-->
</style>  

  </head>
  <body>
  <br/>
  <br/>

  <h1 class="style1"> Access Denied </h1>
  <p class="style3">Your user ID or password is incorrect, or you are not a
     registered user on this site. To try logging in again, click
     <a href="<?=$_SERVER['PHP_SELF']?>">here</a>. To access, please contact our Admin     !</a>.</p>
  </body>
  </html>

<?php
  exit;
}
$username = mysql_result($result,0,'fullname');
$_SESSION['user'] = mysql_result($result,0,'userid');
?>

Answer 1

简单地说

if(mysql_num_rows($result)==0) {
header('location:your_page.php');
}

这会将您重定向到该页面并假设您已定义error()方法，只需

echo error();

使用会话和重定向进行php错误处理

1 个答案: