Question

我有这个查询，但这显示列不存在

SELECT 
p.content,
(select count(*) from share_member WHERE username='pratik' AND share_id=share) as allow 
FROM posts p WHERE allow >="1"

我收到了这个错误

'where子句'中的未知列'allow'

修改已完成此编辑以改进我的使用的SQL查询

SELECT 
p.content,
CASE share_type 
WHEN 'public' then "1"
when 'lsit' then 
    (select count(*) from share_member WHERE username='pratik' AND share_id=share)
end as allow
FROM posts p WHERE allow=>1

错误代码1064，SQL状态42000

Answer 1

您不能在WHERE子句中使用列别名。

但是，您可以使用HAVING子句，在那里可以使用别名。区别在于在构造结果集时执行WHERE，并且在匹配整个集合之后应用HAVING（这意味着HAVING更重要）。

SELECT 
p.content,
(select count(*) from share_member WHERE username='pratik' AND share_id=share) as allow 
FROM posts p
HAVING allow >= 1

编辑：您的第二个查询应如下所示：

SELECT p.content,
  CASE
    WHEN share_type='public' THEN "1"
    WHEN share_type='list' THEN (SELECT COUNT(*) FROM share_member WHERE username='pratik' AND share_id=share)
    END AS `allow`
FROM posts p
HAVING `allow` >= 1

Answer 2

应该是

SELECT p.content,
    (select count(*) 
     from share_member 
     WHERE username='pratik' AND share_id=share) as allow 
FROM posts p 
WHERE (select count(*) 
      from share_member 
      WHERE username='pratik' AND share_id=share) >=1

或

(select count(*) 
 from share_member 
 WHERE username='pratik' AND share_id=share)

应该是from子句，作为另一个结果集

Answer 3

您的查询已修改为

SELECT 
p.content,
(select count(*) from share_member WHERE username='pratik' AND share_id='share') as allow 
FROM posts p WHERE allow >=1

或

SELECT 
p.content,
(select count(*) from share_member WHERE username='pratik' AND share_id='share') as allow 
FROM posts p WHERE allow >='1'

SQL无法正常工作

3 个答案:

或