如何从jQuery获取响应头位置?

时间:2012-06-27 10:17:31

标签: javascript jquery ajax response

所以我试图通过jQuery get从头响应中获取位置。我尝试使用getResponseHeader('Location')和getAllResponseHeaders(),但它们似乎都返回null。

这是我当前的代码

$(document).ready(function(){
   var geturl;
   geturl = $.ajax({
      type: "GET",
      url: 'http://searchlight.cluen.com/E5/Login.aspx?URLKey=uzr7ncj8)',
   });
   var locationResponse = geturl.getResponseHeader('Location');
   console.log(locationResponse);
});

3 个答案:

答案 0 :(得分:30)

异步请求返回时,标题将可用,因此您需要在success callback中阅读它们:

$.ajax({
    type: "GET",
    url: 'http://searchlight.cluen.com/E5/Login.aspx?URLKey=uzr7ncj8)',
    success: function(data, status, xhr) {
        console.log(xhr.getResponseHeader('Location'));
    }
});

答案 1 :(得分:5)

对于jQuery Ajax中的某些头文件,您需要访问XMLHttpRequest对象

var xhr;
var _orgAjax = jQuery.ajaxSettings.xhr;
jQuery.ajaxSettings.xhr = function () {
  xhr = _orgAjax();
  return xhr;
};

$.ajax({
    type: "GET",
    url: 'http://example.com/redirect',
    success: function(data) {
        console.log(xhr.responseURL);
    }
});

或使用普通的javascript

var xhr = new XMLHttpRequest();
xhr.open('GET', "http://example.com/redirect", true);

xhr.onreadystatechange = function () {
  if (this.readyState == 4 && this.status == 200) {
    console.log(xhr.responseURL);
  }
};

xhr.send();

答案 2 :(得分:3)

jQuery在所谓的“超集”中抽象XMLHttpRequest对象,该对象不公开responseURL字段。在他们的文档中,他们谈论“jQuery XMLHttpRequest(jqXHR)对象”

For backward compatibility with XMLHttpRequest, a jqXHR object will expose the following properties and methods:

readyState
responseXML and/or responseText when the underlying request responded with xml and/or text, respectively
status
statusText
abort( [ statusText ] )
getAllResponseHeaders() as a string
getResponseHeader( name )
overrideMimeType( mimeType )
setRequestHeader( name, value ) which departs from the standard by replacing the old value with the new one rather than concatenating the new value to the old one
statusCode( callbacksByStatusCode )
No onreadystatechange mechanism is provided, however, since done, fail, always, and statusCode cover all conceivable requirements.

正如您所看到的那样,无法获取响应URL,因为jqXHR API不会公开它