Question

在其中一个iPad应用程序中，我正在工作，我已将自定义视图添加到视图中。这工作正常，但现在我想删除添加的所有自定义视图。我该怎么做？

以下是我添加自定义视图的代码

for (int col=0; col<colsInRow; col++) {
    //  NSLog(@"Column Number is%d",col);
    x=gapMargin+col*width+gapH*col;


    //self.styleButton=[[UIButton alloc] initWithFrame:CGRectMake(x, y, width, height)];
    ComponentCustomView *componentCustomobject=[[ComponentCustomView alloc] initWithFrame:CGRectMake(x, y, width, height)];
    componentCustomobject.backgroundColor=[UIColor redColor];
    componentCustomobject.componentLabel.text=[appDelegate.componentsArray objectAtIndex:row];
    [self.formConatinerView addSubview:componentCustomobject];
    tempCount1++;
}

Answer 1

您可以从父视图中删除ComponentCustomView类型的所有子视图

for (UIView *view in self.formConatinerView.subviews) {
    if ([view isKindOfClass:[ComponentCustomView class]) {
        [view removeFromSuperview];
    }
}

Answer 2

NSArray  *arr = [self.view subViews];

for (UIView *view in arr) {
    if ([view isKindOfClass:[ComponentCustomView class]) {
        [view removeFromSuperview];
    }
}

Answer 3

我不确定从迭代的数组中移除对象（在这种情况下是subviews）是否安全（我记得读过一些关于Mac OS X和iOS之间的差异，但不确定.. ）;除非属性subviews返回内部数组的副本（很可能因为内部数组需要是可变的），所以100％安全，只是在案例的方式是这样的：

NSArray* copyOfSubviews = [[NSMutableArray alloc] initWithArray:[myView subviews]];
// Explicitly made mutable in an attempt to prevent Cocoa from returning 
//  the same array, instead of making a copy. Another, tedious option would 
//  be to create an empty mutable array and add the elements in subviews one by one.

for(UIView* view in copyOfSubviews){
    if ([view isKindOfClass:[ComponentCustomView class]){
        [view removeFromSuperview];
    }
}

// (This is for non-ARC only:)
[copyOfSubviews release];

如何删除以编程方式添加的自定义视图？

3 个答案: