Question

我有一个在我家中使用分页的对象列表＆gt; index.cshtml。当用户点击每个对象页面时，我只想刷新页面的那一部分，而不是其他任何内容。我该如何做到这一点？

理想情况下，我想使用Async Methods和ControllerActions ......

控制器＆gt; HomeController.cs

public ViewResult Index(int page = 1) {
ProductsListViewModel viewModel = new ProductsListViewModel {
Products = repository.Products
.OrderBy(p => p.ProductID)
.Skip((page - 1) * PageSize)
.Take(PageSize),
PagingInfo = new PagingInfo {
CurrentPage = page,
ItemsPerPage = PageSize,
TotalItems = repository.Products.Count()
}
};
return View(viewModel);
}

主页＆gt; Index.cshtml：

@model SportsStore.WebUI.Models.ProductsListViewModel
@{
ViewBag.Title = "Products";
}
@foreach (var p in Model.Products) {
<div class="item">
<h3>@p.Name</h3>
@p.Description
<h4>@p.Price.ToString("c")</h4>
</div>
}
<div class="pager">
@Html.PageLinks(Model.PagingInfo, x => Url.Action("List", new {page = x}))
</div>

HtmlHelper＆gt; PagingHelper.cs

namespace SportsStore.WebUI.HtmlHelpers {
public static class PagingHelpers {
public static MvcHtmlString PageLinks(this HtmlHelper html,
PagingInfo pagingInfo,
Func<int, string> pageUrl) {
StringBuilder result = new StringBuilder();
for (int i = 1; i <= pagingInfo.TotalPages; i++) {
TagBuilder tag = new TagBuilder("a"); // Construct an <a> tag
tag.MergeAttribute("href", pageUrl(i));
tag.InnerHtml = i.ToString();
if (i == pagingInfo.CurrentPage)
tag.AddCssClass("selected");
result.Append(tag.ToString());
}
return MvcHtmlString.Create(result.ToString());
}
}
}

Answer 1

你可以使用AJAX。第一步是将要刷新的内容放入部分内容并放入其自己的div中：

@model SportsStore.WebUI.Models.ProductsListViewModel
@{
    ViewBag.Title = "Products";
}

<div id="products">
    @Html.Partial("_products", Model.Products)
</div>

<div class="pager">
    @Html.PageLinks(Model.PagingInfo, x => Url.Action("Index", new { page = x }))
</div>

然后你会得到相应的_Products.cshtml部分：

@model IEnumerable<SportsStore.WebUI.Models.ProductViewModel>
@foreach (var p in Model.Products) {
    <div class="item">
        <h3>@p.Name</h3>
        @p.Description
        <h4>@p.Price.ToString("c")</h4>
    </div>
}

然后调整您的控制器操作，以便它能够响应AJAX请求：

public ActionResult Index(int page = 1) 
{
    var viewModel = new ProductsListViewModel 
    {
        Products = repository.Products
            .OrderBy(p => p.ProductID)
            .Skip((page - 1) * PageSize)
            .Take(PageSize),
        PagingInfo = new PagingInfo 
        {
            CurrentPage = page,
            ItemsPerPage = PageSize,
            TotalItems = repository.Products.Count()
        }
    };
    if (Request.IsAjaxRequest())
    {
        return PartialView("_Products", viewModel);
    }

    return View(viewModel);
}

现在剩下的就是AJAX化你的分页锚。可以在一个单独的javascript文件中完成，您可以使用jQuery订阅它们的.click()事件，并用AJAX请求替换默认操作：

$(function() {
     $('.pager a').click(function() {
         $.ajax({
             url: this.href,
             type: 'GET',
             cache: false,
             success: function(products) {
                 $('#products').html(products);
             }
         });

         // prevent the default redirect
         return false;
     });
});

MVC3 - 异步分页

1 个答案: