我需要在LINQ中组合两个查询,这两个查询实际上都来自同一个表。这样做的原因是其中一个查询需要获取每天的字段的最大值,然后将这些日期相加在一起,其中第二个查询可以直接对所有内容求和。这是第一个查询:
var queryDownload = from p in
(from p in almdbContext.cl_contact_event
where p.time_of_contact >= startDate && p.time_of_contact < endDate && p.input_file_name.Contains(inputFileName) && listName.Contains(listName)
group p by new
{
date = EntityFunctions.CreateDateTime(p.time_of_contact.Value.Year, p.time_of_contact.Value.Month, p.time_of_contact.Value.Day, 0, 0, 0),
listName = p.contact_list_name
} into g
select new
{
date = g.Key.date,
listName = g.Key.listName,
download = g.Max(a => a.total_number_of_records)
})
group p by p.listName into g
select new
{
listName = g.Key,
totalDownload = g.Sum(a => a.download),
};
这是第二个:
var queryPenData = from p in almdbContext.cl_contact_event
where p.time_of_contact >= startDate && p.time_of_contact < endDate && p.input_file_name.Contains(inputFileName) && listName.Contains(listName)
group p by p.contact_list_name into g
select new
{
listName = g.Key,
dials = g.Sum(a => a.ov_dial_start_time != null ? 1 : 0),
agentConnects = g.Sum(a => a.agent_login_name != null ? 1 : 0),
abandons = g.Sum(a => a.response_status == "DAC" || a.response_status == "DAD" ? 1 : 0),
rightPartyContacts = g.Sum(a => a.response_status == "PTP" || a.response_status == "RPC" ? 1 : 0),
promiseToPays = g.Sum(a => a.response_status == "PTP" ? 1 : 0),
talkTime = g.Sum(a => EntityFunctions.DiffSeconds(a.ov_call_connected_time, a.ov_trunk_released_time)) ?? 0,
wrapTime = g.Sum(a => EntityFunctions.DiffSeconds(a.ov_trunk_released_time, a.record_released_time)) ?? 0
};
这是将它们连接在一起的查询。
var queryJoin = from qd in queryDownload
join qp in queryPenData
on qd.listName equals qp.listName
select new
{
listName = qp.listName,
download = qd.totalDownload,
dials = qp.dials,
agentConnects = qp.agentConnects,
abandons = qp.abandons,
rightPartyContacts = qp.rightPartyContacts,
promiseToPays = qp.promiseToPays,
talkTime = qp.talkTime,
wrapTime = qp.wrapTime
};
这对我来说似乎非常冗长/迂回。有没有更好的方法可以编写/处理它来缩小/简化代码?
答案 0 :(得分:2)
对于你的上一次查询,你不能只做这样的事吗?
var queryJoin = from qd in queryDownload join qpd in queryPenData on qd.listname equals qpd....
应该能够做到这一点:
var queryJoin = from qd in queryDownload
join qp in queryPenData
on qd.listName equals qp.listName
select new
{
qp, qd
};
据我所知,您已经在queryPenData
中形成了数据,因此没有理由将其重新分配给最终联接中的新变量。只需选择允许您遍历queryPenData
中的匿名类型的对象。我想......