Question

在这里学习一些Java Web开发并尝试启动我的第一个servlet。但是我收到了这个错误：HTTP method GET is not supported by this URL

description The specified HTTP method is not allowed for the requested resource (HTTP method GET is not supported by this URL).

我在html表单中使用'get'方法，正如您所看到的，我已经实现了doget方法。但我不确定为什么我会收到这个错误。它可能与我的web.xml有关吗？

我尝试使用POST方法将html方法更改为'post'并使用doPost方法，但我也得到了相同的错误。我只是这样做测试，我不想使用post。

的web.xml：

<web-app 
    xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">
  <servlet>
     <servlet-name>AppleFox</servlet-name>
     <servlet-class>com.AppleFox.web.ProcessQuery</servlet-class>
  </servlet>

  <servlet-mapping>
     <servlet-name>AppleFox</servlet-name>
     <url-pattern>/ProcessQuery.do</url-pattern>
  </servlet-mapping>
</web-app>

Servlet代码：

package com.AppleFox.web;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class ProcessQuery
 */
public class ProcessQuery<HttpServletRequest> extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();
        String query = ((ServletRequest) request).getParameter("query");

        out.println("Sorry we could find any results for " + query + ".");
    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        return;
    }
}

我也在我的html表单中使用'get'方法。不知道为什么我会收到这个错误。

Answer 1

只需更改以下行并重新排列导入，一切都应该正常工作：

变化：

public class ProcessQuery<HttpServletRequest> extends HttpServlet {

到

public class ProcessQuery extends HttpServlet {

将导入更改为：

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

Answer 2

如果您有兴趣同时使用doget和dopost方法，可以将动作java代码放在proccessRequest（request，response）中并用dopost和doget方法调用它像这样

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package controller;

import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 *
 * @author Birhan
 */
@WebServlet(name = "servlet", urlPatterns = {"/servlet"})
public class servlet extends HttpServlet {

    /**
     * Processes requests for both HTTP <code>GET</code> and <code>POST</code>
     * methods.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.setContentType("text/html;charset=UTF-8");
        try (PrintWriter out = response.getWriter()) {
            /* TODO output your page here. You may use following sample code. */
            out.println("<!DOCTYPE html>");
            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet servlet</title>");            
            out.println("</head>");
            out.println("<body>");
            out.println("<h1>Servlet servlet at " + request.getContextPath() + "</h1>");
            out.println("</body>");
            out.println("</html>");
        }
    }

    // <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
    /**
     * Handles the HTTP <code>GET</code> method.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    /**
     * Handles the HTTP <code>POST</code> method.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    /**
     * Returns a short description of the servlet.
     *
     * @return a String containing servlet description
     */
    @Override
    public String getServletInfo() {
        return "Short description";
    }// </editor-fold>

}

此URL不支持同时获取HTTP方法GET，此URL不支持HTTP方法POST

2 个答案: