我已经看过一些关于jQuery模板的教程,据我所知,这些教程是outdataed,因此我尝试使用.Clone我只是在显示一个结果时才能正常工作,但是当我想要显示时一整个结果列表它不起作用,我确信因为我的错误jQuery。我想克隆整个.template类从响应数组的每个成员填充它,然后将每个新克隆的模板添加到#fillresultsdiv,如果有人可以帮助找到我做错了
这里是jQuery:
success: function (msg) {
var events = [];
var obj = $.parseJSON(msg.d);
$(obj.res).each(function () {
var newRow = $('.template').clone()
newRow.$('.day').text($(this).attr('day')),
newRow.$('.dayofweek').text($(this).attr('dayofweek')),
newRow.$('.month').text($(this).attr('month')),
newRow.$('.title').text($(this).attr('title')),
newRow.$('.time').text($(this).attr('time')),
newRow.$('.venue').text($(this).attr('venue')),
newRow.$('.description').text($(this).attr('description'))
$('#fillresultsdiv').append(newRow);
以下是回复示例:
d: "{"res":[{"day":"26","dayofweek":"Tue","month":"Jun","title":"Glen Hansard","venue":"Vic Theatre","time":"7:00 PM","ticketurl":"http://seatgeek.com/glen-hansard-t
这是我的模板HTML:
<div class="Template">
<div class="accordian_head1">
<div class="date_container">
<a class="day"></a><br/><br/>
<a class="dayofweek"></a><br/>
<a class="month"></a>
</div>
<div class="title_container">
<a class="title">Title</a>
<a class="venue"><br/></a><a class="time"></a>
</div>
<div class="links">
<a href=" + dr(36).ToString() + ?aid=854">Buy Tickets</a><br/>
<a href="javascript:void(0)" onclick="fnAddToCalendar({ 'eventID' : ' dr(0).ToString() + '});">Watch</a><br/>
<a href="#">Email</a><br/>
<a href=""Calendar.aspx"">Calendar</a><br/>
</div>
</div>
<div class="accordian_body1new"><a class="description"></a>
</div>
这都是#fillresultsdiv
<div id="fillresultsdiv"></div>
答案 0 :(得分:1)
试试这个:
success: function (msg) {
var events = [];
var obj = $.parseJSON(msg.d);
$(obj.res).each(function () {
var newRow = $('.template').clone();
newRow.find('.day').text($(this).attr('day'));
newRow.find('.dayofweek').text($(this).attr('dayofweek'));
newRow.find('.month').text($(this).attr('month'));
newRow.find('.title').text($(this).attr('title'));
newRow.find('.time').text($(this).attr('time'));
newRow.find('.venue').text($(this).attr('venue'));
newRow.find('.description').text($(this).attr('description'));
newRow.appendTo('#fillresultsdiv');
}
答案 1 :(得分:1)
// Parse the entire string, because `msg` is not an object,
// so you can't use `msg.d`
var obj = $.parseJSON( msg );
$( obj.d.res ).each( function() {
var newRow = $( '.template' ).clone();
// Now loop through the object
for ( var prop in this ) {
if ( this.hasOwnProperty( prop ) ) {
// Lucky for you, the keys match the classes :)
$( '.' + prop, newRow ).text( this[ prop ] );
}
}
$( '#fillresultsdiv' ).append( newRow );
} );
但是你绝对应该使用DocumentFragment
来加速DOM操作并立即追加所有内容。因为记住: DOM效果很慢。
var obj = $.parseJSON( msg );
// Create a DocumentFragment
var el = document.createDocumentFragment();
$( obj.d.res ).each( function() {
var newRow = $( '.template' ).clone();
for ( var prop in this ) {
if ( this.hasOwnProperty( prop ) ) {
$( '.' + prop, newRow ).text( this[ prop ] );
}
}
// Append to the DocumentFragment
$( el ).append( newRow );
} );
// And append the DocumentFragment to the DIV
$( '#fillresultsdiv' ).append( el );