我发现这篇文章对非ajax请求有用How to handle session expiration and ViewExpiredException in JSF 2? 但是当我使用AJAX调用提交时,我无法使用它。
假设在一个primefaces对话框中,我正在使用AJAX发布一个帖子请求,并且会话已经超时。 我看到我的页面卡住了。
如何解决这种情况,以便当我使用AJAX发布时,我可以将他重定向到我的视图过期页面 然后将他转发到登录页面,类似于上面链接中的解决方案?
JSF2 / Primefaces / Glassfish的
答案 0 :(得分:45)
在ajax请求期间抛出的异常默认情况下在客户端完全没有反馈。只有当您运行Mojarra并将项目阶段设置为Development
并使用<f:ajax>
时,您才会获得带有异常类型和消息的简单JavaScript警报。但除此之外,在PrimeFaces中,默认情况下根本没有反馈。但是,您可以在服务器日志和ajax响应中看到异常(在webbrowser的开发人员工具集的“网络”部分中)。
你需要实现一个自定义ExceptionHandler
,当队列中有ViewExpiredException
时,它基本上可以完成以下工作:
String errorPageLocation = "/WEB-INF/errorpages/expired.xhtml";
context.setViewRoot(context.getApplication().getViewHandler().createView(context, errorPageLocation));
context.getPartialViewContext().setRenderAll(true);
context.renderResponse();
或者,您可以使用JSF实用程序库OmniFaces。它具有FullAjaxExceptionHandler
用于此目的(源代码here,展示演示here)。
答案 1 :(得分:18)
@BalusC和this post的答案合并,我解决了我的问题!
My ExceptionHandlerWrapper:
public class CustomExceptionHandler extends ExceptionHandlerWrapper {
private ExceptionHandler wrapped;
CustomExceptionHandler(ExceptionHandler exception) {
this.wrapped = exception;
}
@Override
public ExceptionHandler getWrapped() {
return wrapped;
}
@Override
public void handle() throws FacesException {
final Iterator<ExceptionQueuedEvent> i = getUnhandledExceptionQueuedEvents().iterator();
while (i.hasNext()) {
ExceptionQueuedEvent event = i.next();
ExceptionQueuedEventContext context
= (ExceptionQueuedEventContext) event.getSource();
// get the exception from context
Throwable t = context.getException();
final FacesContext fc = FacesContext.getCurrentInstance();
final Map<String, Object> requestMap = fc.getExternalContext().getRequestMap();
final NavigationHandler nav = fc.getApplication().getNavigationHandler();
//here you do what ever you want with exception
try {
//log error ?
//log.log(Level.SEVERE, "Critical Exception!", t);
if (t instanceof ViewExpiredException) {
requestMap.put("javax.servlet.error.message", "Session expired, try again!");
String errorPageLocation = "/erro.xhtml";
fc.setViewRoot(fc.getApplication().getViewHandler().createView(fc, errorPageLocation));
fc.getPartialViewContext().setRenderAll(true);
fc.renderResponse();
} else {
//redirect error page
requestMap.put("javax.servlet.error.message", t.getMessage());
nav.handleNavigation(fc, null, "/erro.xhtml");
}
fc.renderResponse();
// remove the comment below if you want to report the error in a jsf error message
//JsfUtil.addErrorMessage(t.getMessage());
} finally {
//remove it from queue
i.remove();
}
}
//parent hanle
getWrapped().handle();
}
}
My ExceptionHandlerFactory:
public class CustomExceptionHandlerFactory extends ExceptionHandlerFactory {
private ExceptionHandlerFactory parent;
// this injection handles jsf
public CustomExceptionHandlerFactory(ExceptionHandlerFactory parent) {
this.parent = parent;
}
@Override
public ExceptionHandler getExceptionHandler() {
ExceptionHandler handler = new CustomExceptionHandler(parent.getExceptionHandler());
return handler;
}
}
我的faces-config.xml
<?xml version='1.0' encoding='UTF-8'?>
<faces-config version="2.2"
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-facesconfig_2_2.xsd">
<factory>
<exception-handler-factory>
your.package.here.CustomExceptionHandlerFactory
</exception-handler-factory>
</factory>
</faces-config>
答案 2 :(得分:3)
我在JBoss 7的生产模式下使用Mojarra 2.1.7。会话到期后,AJAX调用返回错误的XML文档。您可以使用f:ajax的常用onerror处理程序轻松捕获此错误。
<script type="text/javascript">
function showError(data) {
alert("An error happened");
console.log(data);
}
</script>
<h:commandLink action="...">
<f:ajax execute="..." render="..." onerror="showError"/>
</h:commandLink>
答案 3 :(得分:1)
我已将其包含在我的ViewExpiredExceptionHandler类中,它在WAS中对我来说很好用
public void handle() throws FacesException {
FacesContext facesContext = FacesContext.getCurrentInstance();
for (Iterator<ExceptionQueuedEvent> iter = getUnhandledExceptionQueuedEvents()
.iterator(); iter.hasNext();) {
Throwable exception = iter.next().getContext().getException();
if (exception instanceof ViewExpiredException) {
final ExternalContext externalContext = facesContext
.getExternalContext();
try {
facesContext.setViewRoot(facesContext.getApplication()
.getViewHandler()
.createView(facesContext, "/Login.xhtml")); //Login.xhtml is the page to to be viewed. Better not to give /WEB-INF/Login.xhtml
externalContext.redirect("ibm_security_logout?logoutExitPage=/Login.xhtml"); // when browser back button is pressed after session timeout, I used this.
facesContext.getPartialViewContext().setRenderAll(true);
facesContext.renderResponse();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
iter.remove();
}
}
}
getWrapped().handle();
}
希望这有帮助
答案 4 :(得分:1)
我遇到了这个问题,当会话超时后,当用户做任何动作时,需要显示确认弹出窗口,我建议的解决方案是:
<security:http use-expressions="true" auto-config="true" entry-point-ref="authenticationEntryPoint">
<security:intercept-url pattern="/common/auth/**" access="permitAll" />
<security:intercept-url pattern="/javax.faces.resource/**" access="permitAll" />
<security:intercept-url pattern="/**/ *.*" access="hasRole('ROLE_ADMIN')" />
<security:form-login login-page="/common/auth/login.jsf" />
<!-- <security:remember-me key="secret" services-ref="rememberMeServices" /> -->
<security:logout invalidate-session="true" logout-success-url="/common/auth/login.jsf" />
</security:http>
<bean id="authenticationEntryPoint" class="com.x.y.MyRedirectEntryPoint" >
<property name="loginFormUrl" value="/common/auth/login.jsf"/>
</bean>
MyRedirectEntryPoint应扩展AuthenticationProcessingFilterEntryPoint并覆盖begin方法
public void commence(HttpServletRequest request, HttpServletResponse response, AuthenticationException authException)
throws IOException, ServletException {
boolean ajaxRedirect = request.getHeader("faces-request") != null
&& request.getHeader("faces-request").toLowerCase().indexOf("ajax") > -1;
if (ajaxRedirect) {
Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
if (authentication == null) {
response.sendError(403);
}
} else {
super.commence(request, response, authException);
}
}
现在你可以简单地绑定一个回调javascript函数来捕获抛出的403错误并执行你想做的事情:
$(document).bind('ajaxError',
function(event, request, settings, exception){
if (request.status==403){
//do whatever you wanted may be show a popup or just redirect
window.location = '#{request.contextPath}/';
}
});
答案 5 :(得分:1)
对我来说,一个简单的客户端javascript处理程序有效:
function handleAjaxExpired(xhr,status,args) {
// handler for "oncomplete" ajax callback
if ( xhr.responseXML.getElementsByTagName('error-name').length ) {
// "<error-name>" tag is present -> check for "view expired" exception
html = xhr.responseXML.getElementsByTagName('error-name')[0].innerHTML;
if ( html.indexOf('ViewExpiredException') > -1 ) {
// view expired exception thrown
// do something / reload page
if ( confirm('session expired -> reload page?') ) {
document.location.href=document.location.href;
}
}
}
}
此处理程序是在触发UI元素时从“ oncomplete”属性调用的,例如这里来自Primefaces数据表中的rowSelect事件:
<p:ajax event="rowSelect" oncomplete="handleAjaxExpired(xhr,status,args)" />
更新:为避免向每个启用ajax的元素添加“不完整”属性,此javascript代码在所有ajax响应中全局搜索错误:
(function() {
// intercept all ajax requests
var origXHROpen = XMLHttpRequest.prototype.open;
XMLHttpRequest.prototype.open = function() {
this.addEventListener('load', function() {
handleAjaxExpired(this);
});
origXHROpen.apply(this, arguments);
};
})();
此代码使PrimeFaces UI元素中的“不完整”属性过时。