Question

问题1：当我尝试获取每个添加的mc的名称时，我得到最后添加的mC的名称。为什么会这样？我在初级水平。我在互联网上搜索了一段时间但找不到解决方案。 [解决]

问题2：我有4个职位，如何将每个项目（4个vruchtItem）随机地放在其中一个位置，如下一次随机获得其他位置时（如posl位置，banaan at posRight等等）。

public function vruchtenItemKruis(e:Event):void
{       
    var vruchtArray:Array = new Array("Aardbei", "Appel", "Banaan", "Sinaasappel");

    var i:Number= 0;            
    while (i < vruchtArray.length)
    {   

        var vrucht = vruchtArray[i];                

        switch(vrucht)
        {
            case ("Aardbei"):

                vruchtItem = new Aardbei(kruisWeg.width / 2, 50, 50, 65);

                break;

            case ("Appel"):

                vruchtItem = new Appel(kruisWeg.width / 2,  kruisWeg.height - 50, 50, 60);

                break;

            case ("Banaan"):

                vruchtItem = new Banaan(50, kruisWeg.height / 2, 60, 40);

                break;

            case ("Sinaasappel"):

                vruchtItem = new Sinaasappel(kruisWeg.width - 50, kruisWeg.height / 2, 70, 45);

                break;  
        }

        removeEventListener(Event.ADDED_TO_STAGE, vruchtenItemKruis);

        i++;


        addChild(vruchtItem);
        vruchtItem.name = vrucht;

        trace(vruchtItem.name);
        vruchtItem.buttonMode = true;

        vruchtItem.addEventListener(MouseEvent.MOUSE_OVER, vruchtNaam); 

    }
}

public function randomPosXY(xPos:int, yPos:int):int
{
    xPosition = xPos;
    yPosition = yPos;

    // Select an random positie van 4
    var vruchtPos:Array = new Array("posUp",  "posRight", "posDown", "posLeft");
    var randomPos:int =  Math.floor(Math.random() * vruchtPos.length);
    var posXY:String = vruchtPos[randomPos];

    //trace ("random xy started");

    var tot:Number;

    if(posXY)
    {

        while (tot < vruchtPos.length) {
            var itemPos = vruchtPos[tot];

            switch(posXY)
            {
                case ("posUp"):

                    xPosition = kruisWeg.width / 2;
                    yPosition = 0 + 15;

                    break;

                case ("posDown"):

                    xPosition = kruisWeg.width / 2;
                    yPosition = kruisWeg.height - 15;   

                    break;

                case ("posLeft"):

                    xPosition = 0 + 15;
                    yPosition = kruisWeg.height / 2;

                    break;

                case ("posRight"):

                    xPosition = kruisWeg.width - 15;
                    yPosition = kruisWeg.height / 2;

                    break;
            }
        }       
    }


    return xPosition;
    //return yPosition;
}

Answer 1

预先设置您的位置列表，然后在创建每个MC时，从列表中取出一个位置并将其删除。当您添加下一个MC时，将只有3个位置，其中一个随机删除。等等。

Answer 2

你可以为你的随机定位功能做这样的事情。这假设您的四个资产是您传递给该函数的父容器的唯一子项，超级容易让它与您的资产数组一样工作：

public function randomPosXY(itemParent:DisplayObjectContainer):void
{

    var vruchtPos:Array = new Array("posUp",  "posRight", "posDown", "posLeft");

    var xPosition:Number;
    var yPosition:Number;

    var i:int = itemParent.numChildren;
    while (i--) {
    var randomPos:int =  Math.round(Math.random() * (vruchtPos.length - 1));
    switch(vruchtPos[randomPos]) {
        case ("posUp"):
                xPosition = kruisWeg.width / 2;
        yPosition = 0 + 15;

                break;

            case ("posDown"):

                xPosition = kruisWeg.width / 2;
            yPosition = kruisWeg.height - 15;   
            break;

        case ("posLeft"):

            xPosition = 0 + 15;
            yPosition = kruisWeg.height / 2;

            break;

        case ("posRight"):

        xPosition = kruisWeg.width - 15;
        yPosition = kruisWeg.height / 2;
            break;
    }

    //assign position to current item
    itemParent.getChildAt(i).x = xPosition;
    itemParent.getChildAt(i).y = yPosition;

    //remove the used position from the array
    vruchtPos.splice(randomPos, 1);
    }

}

为什么我的MC得到了最后添加的MC的名字？在这种情况下Sinaasappel

2 个答案: