Question

我有3张桌子。

users
------------
id   |  Name   |
------------
44   |   user1 |
45   |useradmin|

Sections
------------
id | Name
------------
1  | Test   |

Assigns
------------
id | u_id | section_id | admin_u_id
-----------------------------------
1  | 44   |    1       |    45     |

我试图提取Assigns表并将u_id和admin_u_id替换为相应的用户名，将section_id替换为部分名称。

到目前为止我所拥有的：

SELECT Assigns.u_id, Assigns.id, users.id,users.id
FROM Assigns
INNER JOIN users
ON Assigns.u_id=users.id
INNER JOIN users
ON Assigns.admin_u_id=users.id
INNER JOIN Sections
ON Assigns.section_id=Sections.id

让我失望的是选择线。我希望它以不同的值显示两次users.id。

非常感谢任何帮助或推动正确的方向。

感谢!!!

编辑：以下是实际的表名。

我的MYSQL查询中没有任何错误，只返回一个空集

SELECT mrfv0_codes_assign.u_id, mrfv0_codes_assign.id, u1.id,u2.id 
FROM mrfv0_codes_assign 
INNER JOIN mrfv0_users u1 ON mrfv0_codes_assign.u_id=u1.id 
INNER JOIN mrfv0_users u2 ON mrfv0_codes_assign.admin_u_id=u2.id 
INNER JOIN mrfv0_codes_sections ON mrfv0_codes_assign.section_id=mrfv0_codes_sections.id

EDIT2：我是一个白痴。我没有正确地摆好桌子。你们都有正确的答案！抱歉浪费你的时间!!!

Answer 1

SELECT a.u_id,
       a.id,
       u1.name AS Username,
       u2.name AS AdminUsername,
       s.name AS SectionName
FROM mrfv0_codes_assign a
INNER JOIN mrfv0_users u1 ON a.u_id = u1.id
INNER JOIN mrfv0_users u2 ON a.admin_u_id = u2.id
INNER JOIN mrfv0_codes_sections s ON a.section_id = s.id

SQL Fiddle Example

<强>输出

| U_ID | ID | USERNAME | ADMINUSERNAME | SECTIONNAME |
------------------------------------------------------
|   44 |  1 |    user1 |     useradmin |        Test |

Answer 2

SELECT Assigns.id AS id,
       users.name AS user_name, 
       admins.name AS admin_name, 
       Sections.name AS section_name
FROM Assigns
INNER JOIN users ON Assigns.u_id = users.id
INNER JOIN users AS admins ON Assigns.admin_u_id = admins.id
INNER JOIN Sections ON Assigns.section_id=Sections.id

只需在INNER JOIN上添加一个别名，它允许您从用户“admin”表中区分用户“user”表。

在这里，您的结果将是这种数组：[id, user_name, admin_name, section_name]

Answer 3

尝试为表分配别名。例如：

SELECT Assigns.u_id, Assigns.id, u1.id,u2.id
FROM Assigns
INNER JOIN users u1
ON Assigns.u_id=u1.id
INNER JOIN users u2
ON Assigns.admin_u_id=u2.id
INNER JOIN Sections
ON Assigns.section_id=Sections.id

2个内连接2个表mysql

3 个答案: