我有这个XSLT 2.0：
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="region/*/*/*
[deep-equal(.,preceding-sibling::*[name()=current()/name()]
[@id = current()/@id]
[../../@id = current()/../../@id][1])]" />
</xsl:stylesheet>
所以基本上任何后续副本（具有相同的名称，ID，方法和子项）都将被移除，直到重置（视为唯一或第一次找到）
如果具有相同和id的节点具有不同的方法，则会发生重置。
为了更清楚，我将这个简化的例子作为插图：
<elem id="1" method="a" />
<elem id="1" method="a" /> <!-- 1. this is duplicate -->
<elem id="1" method="b" /> <!-- 2. this elem id=1 has different method, so it will be the reset point for elem id=1 -->
<elem id="1" method="a" /> <!-- 3. this will be treated as unique because it's reset now so we don't remove this-->
<elem id="2" method="a" /> <!--4.-->
<elem id="1" method="a" /> <!-- this is repetitive for 3 and it willl be removed -->
<elem id="2" method="a" /> <!-- this is repetitive for 4 so we remove this-->
and will be removed -->
转换后，它将简化为：
<elem id="1" method="a" />
<elem id="1" method="b" />
<elem id="1" method="a" /> <!-- 3. this will be treated as unique because it's reset now so we don't remove this-->
<elem id="2" method="a" />
因此，如果它应用于我的XML输入：
<map>
<region>
<gridA id="1">
<blockA id="01" method="build">
<building1 id="x" method="build">
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be removed -->
<otherchild>a</otherchild>
</building1>
</blockA>
<blockA id="01">
<building1 id="x" method="modify"> <!-- this will be the reset point -->
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be kept (prev node have same id but diff method so it's not considered as successive -->
<otherchild>a</otherchild>
</building1>
</blockA>
<blockA id="02">
<building3 id="y" method="modify">
<otherchild>b</otherchild>
</building3>
<building2 id="x" method="demolish"/>
</blockA>
<blockA id="01">
<building1 id="y" method="build"> <!-- this one will be kept (diff id) -->
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be removed -->
<otherchild>a</otherchild>
</building1>
</blockA>
<blockA id="02">
<building3 id="y" method="modify"> <!-- this one will be removed -->
<otherchild>b</otherchild>
</building3>
<building2 id="x" method="demolish"/> <!-- this one will be removed -->
</blockA>
</gridA>
<gridA id="2">
<blockA id="01" method="build">
<building1 id="x" method="build">
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be removed -->
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be kept (diff children) -->
<otherchild>b</otherchild>
</building1>
</blockA>
<blockA id="01">
<building1 id="x" method="build"> <!-- this one will be removed -->
<otherchild>b</otherchild>
</building1>
</blockA>
</gridA>
<gridB id="1">
...and so on..
</gridB>
</region>
</map>
这是预期的输出：
<map>
<region>
<gridA id="1">
<blockA id="01" method="build">
<building1 id="x" method="build">
<otherchild>a</otherchild>
</building1>
</blockA>
<blockA id="01">
<building1 id="x" method="modify"> <!-- this will be the reset point -->
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be kept (prev node have same id but diff method) so it's not considered as successive -->
<otherchild>a</otherchild>
</building1>
</blockA>
<blockA id="02">
<building3 id="y" method="modify">
<otherchild>b</otherchild>
</building3>
<building2 id="x" method="demolish"/>
</blockA>
<blockA id="01">
<building1 id="y" method="build"> <!-- this one will be kept (diff id) -->
<otherchild>a</otherchild>
</building1>
</blockA>
<blockA id="02"/>
</gridA>
<gridA id="2">
<blockA id="01" method="build">
<building1 id="x" method="build">
<otherchild>a</otherchild>
</building1>
<building1 id="x" method="build"> <!-- this one will be kept (diff children) -->
<otherchild>b</otherchild>
</building1>
</blockA>
<blockA id="01"/>
</gridA>
<gridB id="1">
...and so on..
</gridB>
</region>
</map>
同样，如果被比较的两个节点没有共享相同的'gridA'级节点，那么它们不应被视为要删除的重复节点。
我也在考虑使用
<xsl:value-of select="count($this-node/(preceding-sibling::* | ../preceding-sibling::*[@id = $this-node/parent::*/@id]/*)[name() = $this-node/name()][@id = $this-node/@id][deep-equal(*, $this-node/*)][@method = $this-node/@method]) mod 2 = 1"/>
作为我的重置算法，但第一个解决方案更好只需要调整它来处理具有相同id的兄弟姐妹。 （例如，它是：<blockA id="xx">）或者如果有人有更好的解决方案，我真的很想知道。
我希望任何人都能在这个问题上给我启发，因为这对我来说很难理解。
非常感谢并为长期问题道歉。
答案 0 :(得分：3)
看起来您只需将轴从前兄弟更改为前一个并测试相同的'gridA'级父级。
试试这个......
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="region/*/*/*
[deep-equal(.,preceding::* (: Note axis! Look back even past 'block' level :)
[name()=name(current())] (: Compare with same name :)
[@id = current()/@id] (: ... and same id :)
[../.. is current()/../..] (: ... but only within the same 'gridA' level :)
[1] (: Get the first predecessor that satisfies these conditions. :)
)]" />
</xsl:stylesheet>
以上解决方案满足您发布的用例。
我改变了......
../.. = current()/../..
... for ...
../.. is current()/../..