Question

我正在使用PHP从我的mysql数据库中提取mp3文件位置，并希望将这些变量传递给我页面中的脚本。

我想知道如何从我的数据库中的数组中获取以下文件名：

var myCirclePlayer = new CirclePlayer("#jquery_jplayer_1",
{
    m4a:   "downloads/uploads/p170f0vflo1066jbc1l4pp38st01.mp3",
}, {
    cssSelectorAncestor: "#cp_container_1",
    swfPath: "js",
    wmode: "window"
});

所以我需要这样的东西：

var myCirclePlayer = new CirclePlayer("#jquery_jplayer_1",
{
    m4a: "<?php echo $music_p; ?>",  <---This is what I need (from a database)
}, {
    cssSelectorAncestor: "#cp_container_1",
    swfPath: "js",
    wmode: "window"
});

Answer 1

正如@Sean Johnson所说，如果你在与javascript相同的文件中定义$ music_p，它应该可以工作。例如，在javascript标签

中

<?php $music_p = array("downloads/uploads/p170f0vflo1066jbc1l4pp38st01.mp3") ?>

<script type="text/javascript">
//JavaScript code (define functions here)
var myCirclePlayer = new CirclePlayer("#jquery_jplayer_1",
{
m4a: "<?php echo $music_p[0]; ?>",  <----------This is what i want!
}, {
    cssSelectorAncestor: "#cp_container_1",
    swfPath: "js",
    wmode: "window"
});
</script>

我相信这是你可能想要看到的。

在jplayer中嵌入PHP

1 个答案: