我的服务合同
[ServiceContract]
public interface ITsdxService
{
[OperationContract]
[WebGet(UriTemplate="/GetTestCostCentre")]
CostCentre GetTestCostCentre();
[OperationContract]
[WebInvoke(UriTemplate="/SetCostCentre", Method="POST")]
string SetCostCentre(CostCentre cc);
}
public class TsdxService : ITsdxService
{
public CostCentre GetTestCostCentre()
{
CostCentre cc = new CostCentre();
cc.Code = "Test";
cc.Name = "Test Cost Centre";
cc.Description = new byte[] { 12, 34, 89, 240, 66, 87, 189 };
cc.SAPStatus = "Existent";
cc.SAPSiteFolder = "Folder1";
return cc;
}
public string SetCostCentre(CostCentre cc)
{
return cc.Code;
}
}
然后我启动此服务并尝试使用不同的应用程序:
Uri requestUri = new Uri(textBox1.Text + "/tsdx/GetTestCostCentre");
HttpWebRequest request = WebRequest.Create(requestUri) as HttpWebRequest;
XElement root;
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
StreamReader reader = new StreamReader(response.GetResponseStream());
root = XElement.Parse(reader.ReadToEnd());
textBox2.Text = root.ToString();
}
一切都好,我正在获取xml文档。但是当我尝试向此服务发送POST请求时,我遇到了问题:
Uri requestUri = new Uri(textBox1.Text + "/tsdx/SetCostCentre");
HttpWebRequest request = WebRequest.Create(requestUri) as HttpWebRequest;
byte[] bytes = Encoding.UTF8.GetBytes(textBox2.Text);
request.ContentLength = bytes.Length;
request.Method = "POST";
Stream dataStream = request.GetRequestStream();
dataStream.Write(bytes, 0, bytes.Length);
dataStream.Close();
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
StreamReader reader = new StreamReader(response.GetResponseStream());
textBox2.Text = reader.ReadToEnd();
}
异常:远程服务器返回错误:(400)Bad Request。
我做错了什么?
答案 0 :(得分:2)
像这样更改客户端代码
byte[] bytes = Encoding.UTF8.GetBytes(@"<CostCentre xmlns=""http://schemas.datacontract.org/2004/07/WCF_BadRequestService"">
<Code>String content</Code>
<Description>QmFzZSA2NCBTdHJlYW0=</Description>
<Name>String content</Name>
<SAPSiteFolder>String content</SAPSiteFolder>
<SAPStatus>String content</SAPStatus>
</CostCentre>");
request.ContentLength = bytes.Length;
request.Method = "POST";
request.ContentType = "application/xml";
现在没关系。
我认为Java支持WCF BasicHttpBinding,您可以使用Java提供的工具使用WCF服务以简单的方式生成Web服务代理。
答案 1 :(得分:0)
您可能想要做的另一件事是扩展ClientBase,为您完成序列化xml的所有艰苦工作。特别是如果你想支持像json这样的多种消息格式,它将使你的生活变得更加轻松,而且它会对接口编译时错误而不是运行时错误进行任何更改。
public class ITsdxServiceProxy : ClientBase<ITsdxService>, ITsdxService {
#region ITsdxService Members
public CostCentre GetTestCostCentre() {
return Channel.GetTestCostCentre();
}
public string SetCostCentre(CostCentre cc) {
return Channel.SetCostCentre(cc);
}
#endregion
}
在客户端使用
var proxy = new ITsdxServiceProxy();
var costCenter = proxy.GetTestCostCentre();
客户端配置
<system.serviceModel>
<behaviors>
<endpointBehaviors>
<behavior name="web">
<webHttp />
</behavior>
</endpointBehaviors>
</behaviors>
<client>
<endpoint
address="Root address for rest service"
binding="webHttpBinding"
behaviorConfiguration="web"
contract="FullyQualifiedNameOfInterface.ITsdxService">
</endpoint>
</client>
</system.serviceModel>