我有一个在单元格中找到值的算法,对于这种情况,我们可以说单元格是C10。我需要在D列中查看旁边的值,如果该值与我需要的值不匹配,从中获取一个单元格并检查匹配等等。到目前为止我有这个:
bits = []
for row in ws.iter_rows(row_offset=4,column_offset=3):
#skip over empty rows
if row:
#current cell is in column C
cell = row[2]
try:
#find the lowest address in the excel sheet
if cell.internal_value == min(address):
#somehow match up in column d
for '''loop and search col D''':
if str(row[3].internal_value).upper == ('CONTROL 1' or 'CON 1'):
#add bits
for cell in row[4:]:
bits.append(cell.internal_value)
#pass over cells that aren't a number, ie values that will never match an address
except ValueError:
pass
except TypeError:
pass
有办法做到这一点吗?我知道在D列中使用row[3]
比较的比较,但如果第一次不正确,我不知道如何上升列。换句话说,更改row[value]
中的值会在行周围移动,我需要知道在列中移动的值/方式。
谢谢!
答案 0 :(得分:1)
bits = []
min_address = False
for row in ws.iter_rows(row_offset=4,column_offset=3):
c = row[2]
d = row[3]
if not d.internal_value: #d will always have a value if the row isn't blank
if min_address:
break #bits is what you want it to be now
bits = [] #reset bits every time we hit a new row
continue #this will just skip to next row
for bits_cell in row[4:]:
if bits_cell.internal_value:
bits.append(bits_cell.internal_value)
if c.internal_value:
if c.internal_value == min(address):
min_address = True #we set it to true, then kept going until blank row