在WHERE中无效使用组函数SUM()

时间:2012-06-22 11:05:43

标签: mysql subquery sum where

我的查询有问题。

我想在我的WHERE中使用SUM,但它一直让我无效使用组功能。

AND SUM((invoices_out.net+invoices_out.vat)/currencies.rateVsPound)
>
(SELECT SUM(jobs_payments_accounts.amount/currencies.rateVsPound)
 FROM jobs_payments_accounts, jobs, enquiries, currencies
 WHERE jobs_payments_accounts.jobRef = jobs.id
 AND jobs_payments_accounts.currencyRef = currencies.id
 AND enquiries.id = jobs.enquiryRef
 AND enquiries.entityRef = ed.id)

>的右侧效果很好,但我怎样才能达到我想要做的左侧?

这是完整的子查询:

IF(ed.paymentTermsRef = 3,
(SELECT SUM((invoices_out.net+invoices_out.vat)/currencies.rateVsPound)
FROM enquiries, jobs, (SELECT * FROM invoices_out_reference GROUP BY invoiceRef) AS iorUnique,
                                (SELECT enquiryRef, sellingCurrency FROM parts_trading GROUP BY enquiryRef) AS PTU,
                                currencies,
                                invoices_out
                                    WHERE enquiries.entityRef = ed.id
                                    AND enquiries.id = jobs.enquiryRef
                                    AND PTU.enquiryRef = enquiries.id
                                    AND PTU.sellingCurrency = currencies.id
                                    AND jobs.id = iorUnique.jobRef
                                    AND iorUnique.invoiceRef = invoices_out.id
                                    AND invoices_out.paid = 0
                                AND SUM((invoices_out.net+invoices_out.vat)/currencies.rateVsPound)
                                    >
                                    (SELECT SUM(jobs_payments_accounts.amount/currencies.rateVsPound)
                                         FROM jobs_payments_accounts, jobs, enquiries, currencies
                                         WHERE jobs_payments_accounts.jobRef = jobs.id
                                         AND jobs_payments_accounts.currencyRef = currencies.id
                                         AND enquiries.id = jobs.enquiryRef
                                         AND enquiries.entityRef = ed.id)
                                #AND jobs.id NOT IN
                                #       (SELECT jobRef FROM jobs_payments_accounts)
                                #   AND jobs.id NOT IN
                                #       (SELECT jobRef FROM jobs_payments_advance)
                                AND jobs.id IN
                                    (SELECT jobRef FROM invoices_out_reference)
                                AND DATEDIFF(NOW(), invoices_out.date) >= 30),
                                NULL
                             )

尝试使用IS NULL实现您的建议,但它使查询更慢。

对此仍然有很多麻烦,希望我能以某种方式很快破解它。

2 个答案:

答案 0 :(得分:10)

“聚合功能用户俱乐部”的第一条规则是:

  

您不在WHERE

中使用聚合函数

“聚合功能用户俱乐部”的第二条规则是:

  

您不在WHERE

中使用聚合函数
在这种情况下必须使用

HAVING子句:这里a great topic来研究它的一些复杂性。

我真的建议重构你的查询(为什么使用嵌套子查询在三个不同的表中检查jobs.id而不是LEFT JOIN ... ON id IS NULL,例如?)或者用临时表将它分成较小的子表。没有冒犯,但在查看你引用的内容时,我实际上可以听到你的数据库哭声。

答案 1 :(得分:6)

您必须将HAVING与聚合函数一起使用:

select ...
from ...
where ...
group by ...
having sum(...) > ...