Question

给定DateTime start = startsomething和DateTime end = endSomething

是否有一种标准的方法可以在开始和结束时返回所有日期，以便返回的日期列表如...

'1/1/2012 12:00 AM'
'1/2/2012 12:00 AM'

Answer 1

您可以创建一个这样的方法：

public static IEnumerable<DateTime> Range(DateTime start, DateTime end) {
  for (var dt = start; dt <= end; dt = dt.AddDays(1)) {
    yield return dt;
  }
}

Answer 2

您可以填写包含所有日期的列表：

DateTime begin = //some start date
DateTime end = //some end date
List<DateTime> dates = new List<DateTime>();
for(DateTime date = begin; date <= end; date = date.AddDays(1))
{
    dates.Add(date);
}

Answer 3

Linq方式：

DateTime start = new DateTime(2012, 1, 1);
DateTime end = new DateTime(2012, 6, 1);

var list = Enumerable.Range(0, (end - start).Days + 1).Select(i => start.AddDays(i));

Answer 4

您可以使用它来生成日期范围

public static IEnumerable<DateTime> GetDateRange(DateTime startDate, DateTime endDate)
{
  if (endDate < startDate)
    throw new ArgumentException("endDate must be greater than or equal to startDate");

  while (startDate <= endDate)
  {
    yield return startDate;
    startDate = startDate.AddDays(1);
  }
}

然后

GetDateRange(startDate,endDate).Select(d => d.ToString("dd/MM/yyyy hh:mm")).ToArray();

给定开始和结束日期...在C＃中查找范围内的所有日期

4 个答案: