Question

我想获取给定文件夹中具有特定扩展名的所有文件的文件名（并递归地显示其子文件夹）。也就是说，文件名（和扩展名），而不是完整的文件路径。这在Python等语言中非常简单，但我不熟悉C ++中的构造。怎么办呢？

Answer 1

#define BOOST_FILESYSTEM_VERSION 3
#define BOOST_FILESYSTEM_NO_DEPRECATED 
#include <boost/filesystem.hpp>

namespace fs = ::boost::filesystem;

// return the filenames of all files that have the specified extension
// in the specified directory and all subdirectories
void get_all(const fs::path& root, const string& ext, vector<fs::path>& ret)
{
    if(!fs::exists(root) || !fs::is_directory(root)) return;

    fs::recursive_directory_iterator it(root);
    fs::recursive_directory_iterator endit;

    while(it != endit)
    {
        if(fs::is_regular_file(*it) && it->path().extension() == ext) ret.push_back(it->path().filename());
        ++it;

    }

}

Answer 2

在Windows上，您可以执行以下操作：

void listFiles( const char* path )
{
   struct _finddata_t dirFile;
   long hFile;

   if (( hFile = _findfirst( path, &dirFile )) != -1 )
   {
      do
      {
         if ( !strcmp( dirFile.name, "."   )) continue;
         if ( !strcmp( dirFile.name, ".."  )) continue;
         if ( gIgnoreHidden )
         {
            if ( dirFile.attrib & _A_HIDDEN ) continue;
            if ( dirFile.name[0] == '.' ) continue;
         }

         // dirFile.name is the name of the file. Do whatever string comparison 
         // you want here. Something like:
         if ( strstr( dirFile.name, ".txt" ))
            printf( "found a .txt file: %s", dirFile.name );

      } while ( _findnext( hFile, &dirFile ) == 0 );
      _findclose( hFile );
   }
}

在Posix上，如Linux或OsX：

void listFiles( const char* path )
{
   DIR* dirFile = opendir( path );
   if ( dirFile ) 
   {
      struct dirent* hFile;
      errno = 0;
      while (( hFile = readdir( dirFile )) != NULL ) 
      {
         if ( !strcmp( hFile->d_name, "."  )) continue;
         if ( !strcmp( hFile->d_name, ".." )) continue;

         // in linux hidden files all start with '.'
         if ( gIgnoreHidden && ( hFile->d_name[0] == '.' )) continue;

         // dirFile.name is the name of the file. Do whatever string comparison 
         // you want here. Something like:
         if ( strstr( hFile->d_name, ".txt" ))
            printf( "found an .txt file: %s", hFile->d_name );
      } 
      closedir( dirFile );
   }
}

Answer 3

C ++ 17代码

#include <fstream>
#include <iostream>
#include <experimental/filesystem>
namespace fs = std::experimental::filesystem;

int main()
{
    std::string path("/your/dir/");
    std::string ext(".sample");
    for(auto& p: fs::recursive_directory_iterator(path)
    {
        if(p.path().extension() == ext())
            std::cout << p << '\n';
    }
    return 0;
}

Answer 4

获取文件列表并处理每个文件并循环浏览并存储回不同的文件夹

void getFilesList(string filePath,string extension, vector<string> & returnFileName)
{
    WIN32_FIND_DATA fileInfo;
    HANDLE hFind;   
    string  fullPath = filePath + extension;
    hFind = FindFirstFile(fullPath.c_str(), &fileInfo);
    if (hFind != INVALID_HANDLE_VALUE){
        returnFileName.push_back(filePath+fileInfo.cFileName);
        while (FindNextFile(hFind, &fileInfo) != 0){
            returnFileName.push_back(filePath+fileInfo.cFileName);
        }
    }
}

USE：您可以像这样使用加载文件夹中的所有文件并逐个循环

String optfileName ="";        
String inputFolderPath =""; 
String extension = "*.jpg*";
getFilesList(inputFolderPath,extension,filesPaths);
vector<string>::const_iterator it = filesPaths.begin();
while( it != filesPaths.end())
{
    frame = imread(*it);//read file names
        //doyourwork here ( frame );
    sprintf(buf, "%s/Out/%d.jpg", optfileName.c_str(),it->c_str());
    imwrite(buf,frame);   
    it++;
}

Answer 5

你没有说你在使用什么操作系统，但有几种选择。

正如评论者所提到的，boost::filesystem如果可以使用提升，则会有效。

其他选项

Answer 6

这是我的解决方案（适用于* nix系统）：

#include <dirent.h>

bool FindAllFiles(std::string path, std::string type, std::vector<std::string> &FileList){
  DIR *dir;
  struct dirent *ent;
  FileList.clear();

  if ((dir = opendir (path.c_str())) != NULL) {
    //Examine all files in this directory
    while ((ent = readdir (dir)) != NULL) {
      std::string filename = std::string(ent->d_name);
      if(filename.length() > 4){
        std::string ext = filename.substr(filename.size() - 3);
        if(ext == type){
          //store this file if it's correct type
          FileList.push_back(filename);
        }
      }
    }
    closedir (dir);
  } else {
    //Couldn't open dir
    std::cerr << "Could not open directory: " << path << "\n";
    return false;
  }
  return true;
}

显然将所需的扩展名更改为您喜欢的任何内容。还假定使用3个字符的类型。

如何获取给定文件夹中具有特定扩展名的文件列表？

6 个答案: