Question

我想像这个网站http://www.bcaa.it/做一个字符串效果我可以从中学到什么样的脚本或教程？

基本上我想实现与网站相同的功能。有弹跳字符串效果，拖动项目并移走附近的其他项目，拖动和子对象跟随缓动......

Answer 1

嘿，刚刚开始对此进行编码，需要类似于我正在进行的图形显示。这是我的开始，只有两个按钮，但这个想法可以推断/优化：

<?xml version="1.0" encoding="utf-8"?>
<s:WindowedApplication xmlns:fx="http://ns.adobe.com/mxml/2009" 
                       xmlns:s="library://ns.adobe.com/flex/spark" 
                       xmlns:mx="library://ns.adobe.com/flex/mx"
                       creationComplete="windowedapplication1_creationCompleteHandler(event)">

    <fx:Script>
        <![CDATA[
            import mx.events.FlexEvent;

            private var optimalDistanceUpdateTimer:Timer;

            private var optimalDistance:Number = 100;

            private var objectUserGrabbed:Button;

            private var delayDenominator:Number = 6;

            protected function button1_mouseDownHandler(event:MouseEvent):void
            {
                objectUserGrabbed = event.target as Button;
                objectUserGrabbed.startDrag();
            }

            protected function button1_mouseUpHandler(event:MouseEvent):void
            {
                objectUserGrabbed.stopDrag();
            }

            protected function windowedapplication1_creationCompleteHandler(event:FlexEvent):void
            {
                optimalDistanceUpdateTimer = new Timer(33);
                optimalDistanceUpdateTimer.addEventListener(TimerEvent.TIMER, optimalDistanceTickedHandler);
                optimalDistanceUpdateTimer.start();
            }
            private function optimalDistanceTickedHandler(event:TimerEvent):void
            {
                var targetPoint:Point;
                var deltaX:Number;
                var deltaY:Number;

                if(!objectUserGrabbed)
                    return;

                if(objectUserGrabbed == button1)
                {
                    //Basically here I'm playing of Pythagorean theorem for a 45 degree triangle the x component and the y component are the distance of the hypotenuse over Sqrt(2) for different offsets, radially you'd need to adjust this to compute the target point for each object... would do something like var angleForEach:Number = 360/numObjects; then figure out the target point for each of the objects in a loop var angleForThis = angleForEach*index; (in this example only two objects, no loop needed)
                    targetPoint = new Point(objectUserGrabbed.x-optimalDistance/Math.SQRT2, objectUserGrabbed.y-optimalDistance/Math.SQRT2);


                    deltaX = (targetPoint.x-button2.x);
                    deltaY = (targetPoint.y-button2.y);

                    button2.move(button2.x+deltaX/delayDenominator, button2.y+deltaY/delayDenominator);
                }
                else
                {
                    targetPoint = new Point(objectUserGrabbed.x+optimalDistance/Math.SQRT2, objectUserGrabbed.y + optimalDistance/Math.SQRT2);

                    deltaX = (targetPoint.x-button1.x);
                    deltaY = (targetPoint.y-button1.y);

                    button1.move(button1.x+deltaX/delayDenominator, button1.y+deltaY/delayDenominator);
                }
                lineDrawingArea.graphics.clear();
                lineDrawingArea.graphics.lineStyle(1);
                lineDrawingArea.graphics.moveTo(button1.x + button1.width/2,button1.y + button1.height/2);
                lineDrawingArea.graphics.lineTo(button2.x + button2.width/2,button2.y + button2.height/2);
            }
        ]]>
    </fx:Script>

    <fx:Declarations>
        <!-- Place non-visual elements (e.g., services, value objects) here -->
    </fx:Declarations>
    <s:Group id="lineDrawingArea"/>
    <s:Button id="button1" label="Item 1" mouseDown="button1_mouseDownHandler(event)" mouseUp="button1_mouseUpHandler(event)" x="0" y="0"/>
    <s:Button id="button2" label="Item 2" mouseDown="button1_mouseDownHandler(event)" mouseUp="button1_mouseUpHandler(event)" x="0" y="0"/>
</s:WindowedApplication>

如何获得像http://www.bcaa.it/这样的字符串效果

1 个答案: