我正在重新发布这个问题,因为我在第一次发布时犯了一个错误:在问之前我没有努力。我想向社区道歉,要求它为我做我的工作
我试图按字母顺序排序div中的无序列表。不是无序列表中的列表项,而是无序列表本身。
这就是HTML的样子:
<div class="FindByCategory">
<ul>
<li> B. This is the first list item in the second unordered list</li>
<li> B. This is the second list item in the second unordered list</li>
</ul>
<ul>
<li> A. This is the first list item in the first unordered list</li>
<li> A. This is the second list item in the first unordered list</li>
</ul>
</div>
我希望它看起来像这样:
<div class="FindByCategory">
<ul>
<li> A. This is the first list item in the first unordered list</li>
<li> A. This is the second list item in the first unordered list</li>
</ul>
<ul>
<li> B. This is the first list item in the second unordered list</li>
<li> B. This is the second list item in the second unordered list</li>
</ul>
</div>
这是我到目前为止所做的:
<script>
function sortUnorderedList(div.FindByCategory, sortDescending) {
if(typeof div.FindByCategory == "string")
div = document.getElementById(div.FindByCategory);
var uls = ul.getElementsByTagName("UL");
var vals = [];
for(var i = 0, l = uls.length; i < l; i++)
vals.push(uls[i].innerHTML);
vals.sort();
for(var i = 0, l = uls.length; i < l; i++)
uls[i].innerHTML = vals[i];
}
$(function(){
FindByCategory()
}
</script>
答案 0 :(得分:1)
排序任何DOM节点时,有三个简单的步骤:
在这种情况下,您要排序的节点由#FindByCategory > ul
匹配,并且您实际上按其文本内容进行排序。所以:
var qsa = document.querySelectorAll("#FindByCateory > ul"), l = qsa.length, i, arr = [];
for( i=0; i<l; i++) {
arr[i] = [qsa[i],qsa[i].textContent || qsa[i].innerText];
// the text content is not readily accessible, since it depends on the browser
}
// now sort the array:
arr.sort(function(a,b) {return a[1] < b[1] ? -1 : (a[1] == b[1] ? 0 : 1);});
// and now re-append them
for( i=0; i<l; i++) {
arr[i][0].parentNode.appendChild(arr[i][0]);
// by re-appending the nodes, they will emerge sorted
}
答案 1 :(得分:1)
试试这个
<script type="text/javascript">
var array = new Array();
for(var i = 0 ; i<4 ; i++){
var string = $("li:eq("+i+")").text();
array[i] = string;
}
array.sort();
alert(array);
</script>
答案 2 :(得分:0)
这是一个链接到jQuery的瑞士军刀分类插件。 http://tinysort.sjeiti.com/