我将XmlDocument发布到ApiController(从Windows服务,服务工作正常,它发布正确,我在wcf web api中使用它),但xml总是为null,我做错了什么? 我可以发布一些类,例如tutotials,或获取任何数据,一切都会好的,但我不能发布XmlDocument。
public class XmlController : ApiController
{
public void PostXml(XmlDocument xml)
{
// code
}
}
答案 0 :(得分:2)
我按照@Rhot给出的解决方案,但不知何故它不起作用所以我编辑如下,对我有用:
public class XmlMediaTypeFormatter : MediaTypeFormatter
{
public XmlMediaTypeFormatter()
{
SupportedMediaTypes.Add(new MediaTypeHeaderValue("application/xml"));
}
public override bool CanReadType(Type type)
{
return type == typeof(XDocument);
}
public override bool CanWriteType(Type type)
{
return type == typeof(XDocument);
}
public override Task<object> ReadFromStreamAsync(Type type, Stream stream, HttpContent content, IFormatterLogger formatterLogger)
{
var reader = new StreamReader(stream);
string value = reader.ReadToEnd();
var tcs = new TaskCompletionSource<object>();
try
{
var xmlDoc = XDocument.Parse(value);
tcs.SetResult(xmlDoc);
}
catch (Exception ex)
{
//disable the exception and create custome error
//tcs.SetException(ex);
var xml = new XDocument(
new XElement("Error",
new XElement("Message", "An error has occurred."),
new XElement("ExceptionMessage", ex.Message)
));
tcs.SetResult(xml);
}
return tcs.Task;
}
public override Task WriteToStreamAsync(Type type, object value, Stream stream, HttpContent content, TransportContext transportContext)
{
var writer = new StreamWriter(stream);
writer.Write(((XDocument)value).ToString());
writer.Flush();
var tcs = new TaskCompletionSource<object>();
tcs.SetResult(null);
return tcs.Task;
}
}
注册到global.asax:
GlobalConfiguration.Configuration.Formatters.Insert(0, new XmlMediaTypeFormatter());
在我的WebAPI控制器下面:
public HttpResponseMessage Post(XDocument xml)
{
return Request.CreateResponse(HttpStatusCode.OK, xml);
}
答案 1 :(得分:1)
我找到了解决方案:
我们需要使用继承来继承MediaTypeFormatter
public class XmlMediaTypeFormatter : MediaTypeFormatter
{
public XmlMediaTypeFormatter()
{
SupportedMediaTypes.Add(new MediaTypeHeaderValue("text/xml"));
}
public override System.Threading.Tasks.Task<object> ReadFromStreamAsync(Type type, Stream stream,
HttpContentHeaders contentHeaders,
IFormatterLogger formatterLogger)
{
var taskCompletionSource = new TaskCompletionSource<object>();
try
{
var memoryStream = new MemoryStream();
stream.CopyTo(memoryStream);
var s = System.Text.Encoding.UTF8.GetString(memoryStream.ToArray());
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(s);
taskCompletionSource.SetResult(xmlDoc);
}
catch (Exception e)
{
taskCompletionSource.SetException(e);
}
return taskCompletionSource.Task;
}
public override bool CanReadType(Type type)
{
return type == typeof(XmlDocument);
}
public override bool CanWriteType(Type type)
{
return false;
}
}
然后在Global.asax中注册:
GlobalConfiguration.Configuration.Formatters.Insert(0, new XmlMediaTypeFormatter());
控制器:
public HttpResponseMessage PostXml([FromBody] XmlDocument xml)
{//code...}
答案 2 :(得分:0)
PostXml
应该是控制器上的动作吗?如果是这样,您应该将控制器操作标记为接受HttpPost。从那里我将修改动作如下:
[HttpPost]
public ActionResult PostXml(HttpPostedFileBase xml)
{
// code
}
如果您仍然无法接受发布的文件,请启动调试器并检查请求文件集合:http://msdn.microsoft.com/en-us/library/system.web.httprequest.files.aspx