Question

我从未真正用PHP（或任何语言）解析文本。我有这样的文字：

1 (2) ,Yes,5823,"Some Name
801-555-5555",EXEC,,"Mar 16, 2009",0.00,
1 (3) ,,4821,Somebody Else,MBR,,"Mar 11, 2009",,0.00
2 (1) ,,5634,Another Guy,ASSOC,,"Mar 15, 2009",,0.00

你可以看到第一行有一个休息时间，我需要得到它：

1 (2) ,Yes,5823,"Some Name 801-555-5555",EXEC,,"Mar 16, 2009",0.00,
1 (3) ,,4821,Somebody Else,MBR,,"Mar 11, 2009",,0.00
2 (1) ,,5634,Another Guy,ASSOC,,"Mar 15, 2009",,0.00

我正在考虑使用正则表达式在引号内找到\n，或者在引用之后，因为这不会创建错误匹配，然后使用PHP的preg_replace()替换它。我正在研究正则表达式，因为我不知道它有什么，所以我可以自己解决这个问题（这总是最好的）但毫无疑问，我当前问题的解决方案将帮助我更快地处理它

非常感谢。如果可以的话，我会立即给予奖励。

谢谢！

Answer 1

如果文本具有固定格式，也许您根本不需要正则表达式，只需扫描两行双引号，如果只有一行，则开始加入行，直到找到结束行...

如果可以使用转义引号，单引号来分隔字符串等，可能会出现问题，但只要没有那种东西，你应该没问题。

我不懂PHP，所以这里有一些伪代码：

open = False
for line in lines do
    nquotes = line.count("\"")
    if not open then
        if nquotes == 1 then
            open = True
            write(line)
        else #we assume nquotes == 2
            writeln(line)
        end
    else
        if nquotes == 0 then
            write(line)
        else #we assume nquotes == 1
            open = False
            writeln(line)
        end
    end
 end

Answer 2

这基本上是fortran在PHP中的答案

<pre>
<?php

$data = <<<DATA
1 (2) ,Yes,5823,"Some Name
801-555-5555",EXEC,,"Mar 16, 2009",0.00,
1 (3) ,,4821,Somebody Else,MBR,,"Mar 11, 2009",,0.00
2 (1) ,,5634,Another Guy,ASSOC,,"Mar 15, 2009",,0.00
DATA;

echo $data, '<hr>';

$lines = preg_split( "/\r\n?|\n/", $data );

$filtered = "";
$open = false;
foreach ( $lines as $line )
{

  if ( substr_count( $line, '"' ) & 1 && !$open )
  {
    $filtered .= $line;
    $open = true;
  } else {
    $filtered .= $line . "\n";
    $open = false;
  }
}

echo $filtered;
?>
</pre>

如何在文件中的“”中找到\ n

2 个答案: