我有一个有趣的要求来实现。你能帮忙吗? 请查看下表
* * CheckingAccountTable(假设表名 - CAT)
AccountNo TransactionId BalanceID Balance1
123 080 103 $30
123 081 103 $20
123 082 103 $10
123 083 62 $0
123 084 63 $0
123 085 64 $0
123 086 65 $0
123 087 66 $0
124 090 103 $3
124 091 103 $2
124 092 103 $1
124 093 72 $0
124 094 73 $0
124 095 74 $0
124 096 75 $0
124 097 76 $0
SavingsAccountTable(假设表名 - SAT)
BalanceID Balance2
103 $0
62 $15
63 $12
64 $20
65 $0
66 $0
72 $11
73 $0
74 $0
75 $0
76 $0
结果应该看起来像
AccountNo Count(TransactionId) Sum(Balance1+Balance2)
123 6 107
124 4 17
好的,这里,CAT是主表,SAT是返回余额的子表 我想找出transactionID和Sum(Balance1 + Balance 2)的数量
条件。如果Balance1 OR Balance 2为0,我不能将transactionID计入count
通过以下操作无法实现
SELECT T.AccountNo,Count(T.TransactionId),
SUM(T.Balance1 + T.Balance2) 'Stressdays'
FROM
(
SELECT CAT.AccountNo,CAT.Balance1,CAT.BalanceID,CAT,TransactionId
,CASE WHEN SAT.BalanceID= 103 THEN
0
ELSE
SAT.Balance2
END AS 'Balance2'
FROM CAT
INNER JOIN SAT ON CAT.BalanceID = SAT.BalanceID
WHERE CAT.Balance1 <> 0
AND SAT.Balance2 <> 0
)T
GROUP BY T.AccountNo
答案 0 :(得分:3)
如果我了解您的需求,请尝试以下方法:
SELECT cat.AccountNo, Count(TransactionId), SUM(cat.Balance1+sat.Balance2)
FROM cat INNER JOIN sat
ON cat.BalanceID = sat.BalanceID
AND (cat.Balance1 <> 0 OR sat.Balance2 <> 0)
GROUP BY cat.AccountNo
答案 1 :(得分:1)
尝试以下方法:
SELECT CAT.AccountNo,
SUM(CASE WHEN CAT.Balance1 <> 0 OR ISNULL(SAT.Balance2,0) <> 0 THEN 1 ELSE 0 END) CountTransactionId,
SUM(CASE WHEN CAT.Balance1 <> 0 OR ISNULL(SAT.Balance2,0) <> 0 THEN CAT.Balance1+SAT.Balance2 ELSE 0 END) SumBalance1Balance2
FROM CAT
LEFT JOIN SAT
ON CAT.BalanceId = SAT.BalanceId
答案 2 :(得分:1)
SELECT C.AccountNo,Count(C.TransactionId) AS [Count(TransactionId)],
SUM(C.Balance1 + S.Balance2) AS [Sum(Balance1+Balance2)]
FROM SO_CAT C
JOIN SO_SAT S ON S.BalanceID = C.BalanceID-- AND S.BAlance2 <> 0
WHERE C.BALANCE1 <> 0 OR S.BALANCE2 <> 0
GROUP BY C.ACCOUNTNO