Question

任何人都可以帮我使用C＃将XML数据（我从远程 REST服务）插入我的SQL Server数据库吗？

提前致谢。

代码

HttpWebRequest myHttpWebRequest = WebRequest.Create("http://api.asicentral.com/v1/news.xml") as HttpWebRequest;

HttpWebResponse myHttpWebResponse = (HttpWebResponse)myHttpWebRequest.GetResponse();

Encoding enc = System.Text.Encoding.GetEncoding(1252);
StreamReader loResponseStream = 
    new StreamReader(myHttpWebResponse.GetResponseStream(), enc);

string Response = loResponseStream.ReadToEnd();
myHttpWebResponse.Close();

Answer 1

开始学习ADO.Net http://www.csharp-station.com/Tutorial/AdoDotNet/lesson01

或尝试此实体框架代码优先方法http://weblogs.asp.net/scottgu/archive/2010/07/16/code-first-development-with-entity-framework-4.aspx

好的以上内容有点生硬，为什么要将Web服务响应存储到数据库中呢？

要做任何有意义的事情，你可能想要解析xml。你有很多选择。一对情绪浮现在脑海中;将xml反序列化为强类型对象，或者使用linq创建匿名类型。最后，您可以使用ADO.Net或Entity Framework将对象存储到数据库中。

Answer 2

为了将此XML插入SQL Server，您需要在SQL Server中创建一个包含XML类型列的表。

然后你可以使用非常简单的东西：

string connectionString = "......";  // define your connection string here
string query = "INSERT INTO dbo.YourTableNameHere(XmlColumn) VALUES(@XmlContent)";

// set up SqlConnection and SqlCommand
using(SqlConnection conn = new SqlConnection(connectionString))
using(SqlCommand cmd = new SqlCommand(query, conn))
{
    // define parameter for query and set its value to your XML response
    cmd.Parameters.Add("@XmlContent", SqlDbType.VarChar, -1);
    cmd.Parameters["@XmlContent"].Value = Response;    // assign your XML response here

    // open connection, execute INSERT, close connection
    conn.Open();
    cmd.ExecuteNonQuery();
    conn.Close();     
}

当然，如果你使用像Entity Framework或其他一些ORM这样的东西，那么事情看起来会有很多不同......这只是“直接”纯ADO.NET

Answer 3

    [WebMethod]
    public void XMLPersing()
    {
        var XMLDATA = "";

        WriteLogCLS objWriteLog = new WriteLogCLS();
        Stream receiveStream = HttpContext.Current.Request.InputStream;
        receiveStream.Position = 0;
        StreamReader readStream = new StreamReader(receiveStream, Encoding.UTF8);      //For xml persing..
        XMLDATA = readStream.ReadToEnd();
        readStream.Close();

      objWriteLog.WriteLog(Convert.ToString(XMLDATA));
        XmlTextReader xmlreader = new XmlTextReader(Server.MapPath("Log/Exception/Sample.xml"));
        DataSet ds = new DataSet();
        ds.ReadXml(xmlreader);
        xmlreader.Close();
        if (ds.Tables.Count != 0)
        {
            var strCon = string.Empty;
            strCon = ConfigurationManager.AppSettings["constring"];
            SqlCommand cmdInsertXMLData = new SqlCommand();
            SqlConnection SqlConn;
            SqlConn = new SqlConnection(strCon);
            try
            {
                cmdInsertXMLData = new SqlCommand("usp_InsertXML", SqlConn);
                cmdInsertXMLData.CommandType = CommandType.StoredProcedure;
                // cmdInsertLoginDetails.Parameters.Add("@XMLdata", SqlDbType.Xml).Value = ds.GetXml();
                cmdInsertXMLData.Parameters.AddWithValue("@XMLdata", SqlDbType.Xml);

                if (SqlConn.State == ConnectionState.Closed)
                {
                    SqlConn.Open();
                }
                cmdInsertXMLData.ExecuteNonQuery();
                // response = cmdInsertLoginDetails.Parameters["@Message"].Value.ToString();
            }
            catch (Exception ex)
            {
                objWriteLog.WriteLog("Error on XML Persing : " + ex.Message);
                // response = "Error";
            }
            finally
            {
                if (cmdInsertXMLData != null)
                {
                    cmdInsertXMLData.Dispose();
                }
                if (SqlConn.State == ConnectionState.Open)
                {
                    SqlConn.Close();
                    SqlConn.Dispose();
                }
                objWriteLog = null;
            }
            // return response  ;

        }
    }
}

使用C＃将REST服务中的XML数据插入到DB中

3 个答案: