Question

public class WeeklyInspection : Activity
{
  WebView view = (WebView) FindViewById(Resource.Id.inspectionWV);
  view.Settings.JavaScriptEnabled = true;
  view.Settings.CacheMode = CacheModes.CacheElseNetwork;
  view.SetWebChromeClient(new CustomWebChromeClient(this));
  view.SetWebViewClient(new CustomWebViewClient(this));
  view.LoadUrl("http://myurl.com");
}

private class CustomWebChromeClient: WebChromeClient
{
   public override void OnConsoleMessage(string message, int lineNumber, string sourceID)
    {
       if (message.StartsWith("Submit")
          //do all my submit stuff here
          //if without error, I want to go back to the Main Activity.  Have tried:
          Intent intent = new Intent(BaseContext, typeof(Main));
          StartActivity(intent); //Both BaseContext and StartActivity throw "Cannot access non-static method in static context"
          //tried:
          Finish(); //Same thing
          //tried:
          OnBackPressed(); //Same thing
    }
}

Answer 1

只需使用

Application.Context.StartActivity(intent);

Answer 2

当您遇到状态的编译器错误消息时，StartActivity是Context的实例方法，而不是静态方法，因此无法像这样调用。

您没有将它包含在代码示例中，但是在活动中您将“this”（活动）传递给CustomWebChromeClient的构造函数，因此我假设CustomWebChromeClient保留对它的引用。您可以使用该引用来调用活动所需的实例方法，无论是StartActivity，Finish还是其他任何您需要的方法。例如：

private class CustomWebChromeClient: WebChromeClient
{
    private readonly Activity _context;

    public CustomWebChromeClient(Activity context) 
    {
        _context = context;
    }

    public override void OnConsoleMessage(string message, int lineNumber, string sourceID)
    {
        if (message.StartsWith("Submit"))
        {
            _context.Finish();
        }
    }
}

来自Class的Android Start Activity

2 个答案: