Question

我想询问是否有更快的方法来进行此查询？实际上完成需要大约100秒。我在表中有大约10 000 000（1 GB）行。这是统计信息生成脚本。

这是查询：

  $results=mysql_query("SELECT * FROM hawkeye WHERE player_id='".$playerID."'") or die("MYSQL ERROR: ".mysql_error());

然后是php代码：

  $row = mysql_fetch_array($results)
  if($row["action"] == 4){$commandcount++;}
  else if($row["action"] == 3){$chatcount++;}
  else if($row["action"] == 1){$placedcount++;}
  else if($row["action"] == 0){$breakcount++;}
  else if($row["action"] == 5){$joincount++;}
  else if($row["action"] == 6){$quitcount++;}
  else if($row["action"] == 7){$qteleportcount++;}
  else if($row["action"] == 12){$pvpdeathcount++;}
  else if($row["action"] == 21){$mobkillcount++;}
  else if($row["action"] == 22){$otherdeathcount++;}
  else {}

感谢您的回答！

Answer 1

使用MYSQL为您做数学运算。它比PHP更快：

SELECT COUNT(*) AS action_count
     , action
FROM hawkeye 
WHERE player_id='".$playerID."'"
GROUP BY action

while ($row = mysql_fetch_assoc($result))
{
    echo $row['action'] . ': ' . $row['action_count'] . "<br>" . PHP_EOL;
}

Answer 2

怎么样？

SELECT action, count(*) FROM hawkeye WHERE player_id='$playerID' GROUP BY action

因此，您只会按操作类型循环一次，而不是每操作

一次

Answer 3

看来你正在尝试做一些计算。尝试进行聚合和/或使用分析数据库，如infobright，将聚合存储在内存中。避免执行SELECT *并执行实际的SELECT column1，column2。主要是阅读做SUM，COUNT Group BY和Order By等聚合。

Answer 4

$results=mysql_query("SELECT action, count(*) as `cnt` FROM hawkeye WHERE player_id='".$playerID."' GROUP BY action") or die("MYSQL ERROR: ".mysql_error());

while ($row = mysql_fetch_array($results)) {
  if($row["action"] == 4){$commandcount=$row["cnt"];}
  else if($row["action"] == 3){$chatcount=$row["cnt"];}
  else if($row["action"] == 1){$placedcount=$row["cnt"];}
  else if($row["action"] == 0){$breakcount=$row["cnt"];}
  else if($row["action"] == 5){$joincount=$row["cnt"];}
  else if($row["action"] == 6){$quitcount=$row["cnt"];}
  else if($row["action"] == 7){$qteleportcount=$row["cnt"];}
  else if($row["action"] == 12){$pvpdeathcount=$row["cnt"];}
  else if($row["action"] == 21){$mobkillcount=$row["cnt"];}
  else if($row["action"] == 22){$otherdeathcount=$row["cnt"];}
  else {}
}

Answer 5

为按player_id索引的鹰眼表添加索引，并遵循John Conde的建议。

真的很大的SELECT查询

5 个答案: