python unhashable type - 发布xml数据

时间:2012-06-18 12:10:41

标签: python typeerror httplib

首先,我不是python程序员。我是一个老C狗,学习了新的Java和PHP技巧,但python看起来很酷。

我收到一个我无法理解的错误。该错误遵循以下代码。

import httplib, urllib
url = "pdb-services-beta.nipr.com"
xml = '<?xml version="1.0"?><!DOCTYPE SCB_Request SYSTEM "http://www.nipr.com/html/SCB_XML_Request.dtd"><SCB_Request Request_Type="Create_Report"><SCB_Login_Data CustomerID="someuser" Passwd="somepass" /><SCB_Create_Report_Request Title=""><Producer_List><NIPR_Num_List_XML><NIPR_Num NIPR_Num="8980608" /><NIPR_Num NIPR_Num="7597855" /><NIPR_Num NIPR_Num="10166016" /></NIPR_Num_List_XML></Producer_List></SCB_Create_Report_Request></SCB_Request>'

params = {}
params['xmldata'] = xml

headers = {}
headers['Content-type'] = 'text/xml'
headers['Accept'] = '*/*'
headers['Content-Length'] = "%d" % len(xml)

connection = httplib.HTTPSConnection(url)
connection.set_debuglevel(1)
connection.request("POST", "/pdb-xml-reports/scb_xmlclient.cgi", params, headers)

response = connection.getresponse()
print response.status, response.reason
data = response.read()
print data
connection.close

这是错误:

Traceback (most recent call last):   
 File "C:\Python27\tutorial.py", line 14, in  connection.request("POST", "/pdb-xml-reports/scb_xmlclient.cgi", params, headers)   
 File "C:\Python27\lib\httplib.py", line 958, in request self._send_request(method, url, body, headers)   
 File "C:\Python27\lib\httplib.py", line 992, in _send_request self.endheaders(body)
 File "C:\Python27\lib\httplib.py", line 954, in endheaders self._send_output(message_body)
 File "C:\Python27\lib\httplib.py", line 818, in _send_output self.send(message_body)
 File "C:\Python27\lib\httplib.py", line 790, in send self.sock.sendall(data)
 File "C:\Python27\lib\ssl.py", line 229, in sendall v = self.send(data[count:]) 
TypeError: unhashable type

我的日志文件说xmldata参数为空。

有什么想法吗?

2 个答案:

答案 0 :(得分:2)

我猜params在传递给.request时必须是一个字符串,这可以解释错误,因为哈希是不可哈希的事实

首先尝试使用

对params进行编码
params = urllib.urlencode(params)

您可以在底部找到另一个代码示例:

http://docs.python.org/release/3.1.5/library/http.client.html

答案 1 :(得分:0)

感谢您的反馈。

我想我太难了。我走了一条不同的路,似乎有效。

import urllib2
URL = "https://pdb-services-beta.nipr.com/pdb-xml-reports/scb_xmlclient.cgi"
DATA = 'xmldata=<?xml version="1.0"?><!DOCTYPE SCB_Request SYSTEM "http://www.nipr.com/html/SCB_XML_Request.dtd"><SCB_Request Request_Type="Create_Report"><SCB_Login_Data CustomerID="someuser" Passwd="somepass" /><SCB_Create_Report_Request Title=""><Producer_List><NIPR_Num_List_XML><NIPR_Num NIPR_Num="8980608" /></NIPR_Num_List_XML></Producer_List></SCB_Create_Report_Request></SCB_Request>'
req = urllib2.Request(url=URL, data=DATA)
f = urllib2.urlopen(req)
print f.read()