Question

请帮助我加入命令的结果（MS SQL）：

SELECT name,value FROM table1  WHERE idfoo1 IN(SELECT _id FROM table3 where id = 1);
SELECT value FROM table2  WHERE idfoo2 IN(SELECT _id_2 FROM table3 where id = 1) AND name='fooname';

我得到了：

name  value 
John  2     
Bill  32    
Alex  11   

value
434
234
144

但我需要加入结果。

name  value value
John  2     434
Bill  32    234
Alex  11    144

所以，id == id，_id！= _id_2，

Answer 1

使用此查询：

SELECT t1.name,
       t1.value,
       t2.value
FROM table1 t1
INNER JOIN table3 t3 ON t1.idfoo1 = t3._id
INNER JOIN table2 t2 ON t2.idfoo2 = t3._id_2
WHERE t3.id=1 AND t2.name = 'fooname'

Answer 2

Select  a.name,a.value,c.value FROM table1  as a inner join table3 as b
on a.idfoo1=b.id and b.id=1 inner join table3 as c
on c.idfoo2=b._id_2 and b.id=1 and c.name='fooname'

Answer 3

我想这就是你所需要的 -

SELECT t1.name, t1.value, t2.value
FROM table1 t1, table2 t2, table3 t3 
WHERE 
   t1.idfoo1 = t3._id
   AND t2.idfoo2 = t3._id_2
   AND t3.id = 1
   AND t2.name='fooname';

加入sql结果

3 个答案: