Question

假设我有一个像Java这样的2D数组（矩阵）......

int[][] MyMat = {{0,1,2,3,4}, {9,8,7,6,5}};

如果我想提取列，我可以像这样轻松地完成...

int[] My0= MyMat[0]; //My0 = {0,1,2,3,4}
int[] My1= MyMat[1]; //My1 = {9,8,7,6,5}

但是如何提取行？...

int[] My_0= ?; //My_0 = {0,9}
int[] My_1= ?; //My_1 = {1,8}
int[] My_2= ?; //My_2 = {2,7}
int[] My_3= ?; //My_3 = {3,6}
int[] My_4= ?; //My_4 = {4,5}

有没有实现此目的的简写？

Answer 1

如果要获取行，则需要从每个数组中获取值，然后根据值创建新数组。您可以手动分配值，也可以使用for循环，例如this ...

int[][] MyMat = {{0,1,2,3,4}, {9,8,7,6,5}};

// get your columns... (easy)
int[] My0= MyMat[0]; //My0 = {0,1,2,3,4}
int[] My1= MyMat[1]; //My1 = {9,8,7,6,5}

// get the rows... (manually)
int[] My_0= new int[]{MyMat[0][0],MyMat[1][0]}; //My_0 = {0,9}
int[] My_1= new int[]{MyMat[0][1],MyMat[1][1]}; //My_1 = {1,8}
int[] My_2= new int[]{MyMat[0][2],MyMat[1][2]}; //My_2 = {2,7}
int[] My_3= new int[]{MyMat[0][3],MyMat[1][3]}; //My_3 = {3,6}
int[] My_4= new int[]{MyMat[0][4],MyMat[1][4]}; //My_4 = {4,5}

// get the rows... (as a for-loop)
int size = MyMat.length;
int[] My_0 = new int[size]; //My_0 = {0,9}
int[] My_1 = new int[size]; //My_1 = {1,8}
int[] My_2 = new int[size]; //My_2 = {2,7}
int[] My_3 = new int[size]; //My_3 = {3,6}
int[] My_4 = new int[size]; //My_4 = {4,5}
for (int i=0;i<size;i++){
    My_0[i] = MyMat[i][0];
    My_1[i] = MyMat[i][1];
    My_2[i] = MyMat[i][2];
    My_3[i] = MyMat[i][3];
    My_4[i] = MyMat[i][4];
}

否则，转动整个阵列，使其存储{row,column}而不是{column,row}，就像这样......

int[][] MyMat = {{0,9},{1,8},{2,7},{3,6},{4,5}};

// get the rows... (easy)
int[] My_0= MyMat[0]; //My_0 = {0,9}
int[] My_1= MyMat[1]; //My_1 = {1,8}
int[] My_2= MyMat[2]; //My_2 = {2,7}
int[] My_3= MyMat[3]; //My_3 = {3,6}
int[] My_4= MyMat[4]; //My_4 = {4,5}

// get the columns... (manually)
int[] My0= new int[]{MyMat[0][0],MyMat[1][0],MyMat[2][0],MyMat[3][0],MyMat[4][0]}; //My0 = {0,1,2,3,4}
int[] My1= new int[]{MyMat[0][1],MyMat[1][1],MyMat[2][1],MyMat[3][1],MyMat[4][1]}; //My1 = {9,8,7,6,5}

// get the columns... (as a for-loop)
int size = MyMat.length;
int[] My0 = new int[size]; //My0 = {0,1,2,3,4}
int[] My1 = new int[size]; //My1 = {9,8,7,6,5}
for (int i=0;i<size;i++){
    My0[i] = MyMat[0][i];
    My1[i] = MyMat[1][i];
}

请注意，不可能有一个简单的方法，可以让你轻松获得行和列 - 你必须决定你想要更多，并将数组结构化为该格式。 / p>

Answer 2

如果我们知道二维数组的大小行和列大小，我们可以在上面实现如下

让行数 - 行

让列号为-clmns

int[][] my = new int[clmns][rows];
for(int i=0;i<clmns;i++)
for(int j=0;j< rows; j++)
 my[i][j]=MyMat[j][i];

然后在时间上取一列给出原始数组的行数组。

否则，如果在程序运行时给出了no.of行，则可以使用Array of ArrayList和行的数组长度。

Answer 3

这很简单：

1。转置您的2D矩阵 2。然后你做meint [] My0 = MyMat [0]; int [] My1 = MyMat [1];

从Java中获取2D阵列矩阵中的行和列

3 个答案: