不幸的是,我有两个循环。这就是为什么我的代码使第一个循环运行的原因,只有当它完成时,才会使第二个循环运行。
但我希望gui同时显示数据:在hAxes和loading1中。
我该怎么做?
hFigure = figure('units','pixels','position',[300 300 424 470],'menubar','none',...
'name','start processing','numbertitle','off','resize','off');
hAxes = axes('Parent',hFigure,'Units','pixels','Position',[0 112 424 359]);
loading1 = uicontrol('style','text','unit','pix','position',[0 72 424 40],...
'backgroundcolor','r','fontsize',20);
%% shows the data on hAxes
for i = 5:100
if mod(i,2) == 0
set(hAxes,'Color','b');
else
set(hAxes,'Color','g');
end
drawnow;
end
%% shows the data on loading1
for i=1:200
image2 = horzcat('now processing ', 'image', num2str(i), '.jpg of 200 images');
set(loading1,'string',image2);
drawnow;
end
这段代码是彼得:
function test1
hFigure = figure('units','pixels','position',[300 300 424 470],'menubar','none','name','start processing','numbertitle','off','resize','off');
% Your other setup calls
hAxes = axes('Parent',hFigure,'Units','pixels','Position',[0 112 424 359]);
loading1 = uicontrol('style','text','unit','pix','position',[0 72 424 40],'backgroundcolor','r','fontsize',20);
c = 1;
t = timer('TimerFcn', @color_change_fcn,'StartDelay',1.0);
start(t);
for i=1:200
image2 = horzcat('now processing ', 'image', num2str(i), '.jpg of 200 images');
set(loading1,'string',image2);
drawnow;
end
function color_change_fcn
if mod(c,2) == 0
set(hAxes,'Color','b');
else
set(hAxes,'Color','g');
end
drawnow;
c = c + 1;
end
end
它不起作用(不显示hAxes)。我看到它没有使color_change_fcn运行(我试着在color_change_fcn函数的第一行写:disp('test'),但它什么都没打印。
答案 0 :(得分:1)
for i=1:200
if mod(i,2) == 0
set(hAxes,'Color','b');
else
set(hAxes,'Color','g');
end
image2 = horzcat('now processing ', 'image', num2str(i), '.jpg of 200 images');
set(loading1,'string',image2);
drawnow;
end
编辑:好的,在这种情况下,请尝试使用计时器而不是第一个循环
function output = main_function
% Your other setup calls
hAxes = axes('Parent',hFigure,'Units','pixels','Position',[0 112 424 359]);
c = 0;
t = timer('TimerFcn', @color_change_fcn, 'Period', 1.0);
start(t);
for i=1:200
image2 = horzcat('now processing ', 'image', num2str(i), '.jpg of 200 images');
set(loading1,'string',image2);
drawnow;
end
function color_change_fcn
if mod(c,2) == 0
set(hAxes,'Color','b');
else
set(hAxes,'Color','g');
end
drawnow;
c = c + 1;
end
end
请记住,MATLAB控制流本质上是单线程的,因此如果MATLAB在其他地方忙着工作,这些回调将无法运行。
答案 1 :(得分:1)
这似乎与您的previous question有关,您希望两个循环同时运行(至少看起来是这样)。
根据@Peter的答案,请考虑以下工作示例:
function timerDemo()
%# prepare GUI
hFig = figure('Menubar','none', 'Resize','off');
axes('XLim',[0 1], 'YLim',[0 1], 'Visible','off', ...
'Units','normalized', 'Position',[0.1 0.2 0.8 0.6])
hTxt = uicontrol('Style','text', 'FontSize',24, ...
'Units','normalized', 'Position',[0 0.9 1 0.1]);
hPatch = patch([0 0 1 1 0],[0 1 0 1 0],'k');
%# colors to cycle through
c = 1;
clr = lines(4);
%# create timer
delay = 0.5;
hTimer = timer('Period',delay, 'StartDelay',delay, ...
'ExecutionMode','FixedRate', 'TimerFcn',@timerCallback);
%# when figure is closed
set(hFig, 'CloseRequestFcn',@onClose);
%# process images
start(hTimer); %# start timer
for i=1:100
if ~ishandle(hFig), break; end
msg = sprintf('Processing image %d / %d', i, 100);
set(hTxt, 'String',msg)
%# some lengthy operation
pause(.1)
end
if isvalid(hTimer)
stop(hTimer) %# stop timer
delete(hTimer) %# delete timer
end
%# timer callback function
function timerCallback(src,evt)
if ~ishandle(hFig), return; end
%# incremenet counter circularly
c = rem(c,size(clr,1)) + 1;
%# update color of patch
set(hPatch, 'FaceColor',clr(c,:));
drawnow
end
%# on figure close
function onClose(src,evt)
%# stop and delete timer
if isvalid(hTimer)
stop(hTimer);
delete(hTimer);
end
%# call default close callback
feval(@closereq)
end
end
代码模拟在多个图像上运行冗长的处理步骤,同时显示动画以保持用户娱乐。
为了保持代码简单,我正在显示一个连续更新颜色的补丁(使用计时器)。这代表“{...}”的animated GIF image。