我有一个CATextlayer
的特定大小和NSAttributedString
未知长度的文字。
我需要调整字体大小,以便文本适合框架(反之亦然:)
任何想法从哪里开始? :)
[编辑]正如nall指出的那样,我可以确定字符串长度,当然,这是用户输入的一些文本,我需要将其放入一个固定大小的框中。
答案 0 :(得分:6)
我通过这样做实现了它:
float fontSize = InitialFontSize;
UIFont *myFont = [UIFont boldSystemFontOfSize:fontSize];
CGSize myFontSize = [YourTextHere sizeWithFont:myFont];
while (myFontSize.width >= MaximunWidth) {
fontSize -= 0.1f;
myFont = [UIFont boldSystemFontOfSize:fontSize];
myFontSize = [YourTextHere sizeWithFont:myFont];
}
CATextLayer *textLayer = [CATextLayer layer];
[textLayer setFrame:CGRectMake(MaximunWidth - myFontSize.width / 2, MaximunHeight - myFontSize.height / 2, myFontSize.width, myFontSize.height)];
[textLayer setFontSize:fontSize];
[textLayer setString:YourTextHere];
[textLayer setAlignmentMode:kCAAlignmentCenter];
答案 1 :(得分:1)
我最终这样做了:
textlayer
是CATextlayer
theString
是NSMutableAttributedString
是的,它不是很优雅,绝对可以改进;)
CTFramesetterRef framesetter = CTFramesetterCreateWithAttributedString((__bridge CFAttributedStringRef)theString);
CGRect columnRect = CGRectMake(0, 0 , 320, 150);
CGMutablePathRef path = CGPathCreateMutable();
CGPathAddRect(path, NULL, columnRect);
CTFrameRef frame = CTFramesetterCreateFrame(framesetter, CFRangeMake(0, 0), path, NULL);
CFRange frameRange = CTFrameGetVisibleStringRange(frame);
int fontSize = 18;
while(theString.string.length > frameRange.length){
fontSize--;
CFStringRef fontName = (__bridge CFStringRef)[defs objectForKey:@"font"];
CTFontRef font = CTFontCreateWithName(fontName, fontSize, NULL);
[theString addAttribute:(NSString *)kCTFontAttributeName
value:(__bridge id)font
range:NSMakeRange(0, theString.string.length)];
CTFramesetterRef framesetter = CTFramesetterCreateWithAttributedString((__bridge CFAttributedStringRef)theString);
CGRect columnRect = CGRectMake(0, 0 , 320, 150);
CGMutablePathRef path = CGPathCreateMutable();
CGPathAddRect(path, NULL, columnRect);
CTFrameRef frame = CTFramesetterCreateFrame(framesetter, CFRangeMake(0, 0), path, NULL);
frameRange = CTFrameGetVisibleStringRange(frame);
textLayer.string = theString;
}
答案 2 :(得分:0)
我相信你问的问题与this question相同。
看起来您必须迭代各种字体大小以确定哪种字体适合您的矩形。
答案 3 :(得分:0)
为 Swift 5 干净解决方案工作。
1)扩展字符串
extension String {
func size(OfFont font: UIFont) -> CGSize {
return (self as NSString).size(withAttributes: [NSAttributedString.Key.font: font])
}
}
2)子类化CATextLayer
class DynamicTextLayer : CATextLayer {
var adjustsFontSizeToFitWidth = false
override func layoutSublayers() {
super.layoutSublayers()
if adjustsFontSizeToFitWidth {
fitToFrame()
}
}
func fitToFrame(){
// Calculates the string size.
var stringSize: CGSize {
get { return (string as? String)!.size(OfFont: UIFont(name: (font as! UIFont).fontName, size: fontSize)!) }
}
// Adds inset from the borders. Optional
let inset: CGFloat = 2
// Decreases the font size until criteria met
while frame.width < stringSize.width + inset {
fontSize -= 1
}
}
}
3)现在转到您的代码,使用DynamicTextLayer代替CATextLayer
textLayer = DynamicTextLayer()
textLayer?.alignmentMode = .center
textLayer?.fontSize = 40
textLayer?.string = "Example"
textLayer?.adjustsFontSizeToFitWidth = true
答案 4 :(得分:-1)
CATextLayer *textLayer;
[textLayer setWrapped: TRUE];
希望这将有效