您好我正在尝试将图像从URL添加到ImageView我尝试将其加载为位图但没有显示任何内容。那么有谁知道这样做的最佳方法是什么,或者我做错了什么?
继承我的代码
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
//Check Preferences which sets UI
setContentView(R.layout.singlenews);
TextView headerText = (TextView) findViewById(R.id.header_text);
headerText.setText("Latest News");
PostTask posttask;
posttask = new PostTask();
posttask.execute();
}
public void loadNews(){
newsStr = getIntent().getStringExtra("singleNews");
try {
JSONObject obj = new JSONObject(newsStr);
content = obj.getString("content");
title = obj.getString("title");
fullName = obj.getString("fullname");
created = obj.getString("created");
NewsImageURL = obj.getString("image_primary");
tagline = obj.getString("tagline");
meta = "posted by: " + fullName + " " + created;
URL aURL = new URL("NewsImageURL");
URLConnection conn = aURL.openConnection();
conn.connect();
InputStream is = conn.getInputStream();
/* Buffered is always good for a performance plus. */
BufferedInputStream bis = new BufferedInputStream(is);
/* Decode url-data to a bitmap. */
bm = BitmapFactory.decodeStream(bis);
bis.close();
is.close();
/* Apply the Bitmap to the ImageView that will be returned. */
Log.v("lc", "content=" + content);
Log.v("lc", "title=" + title);
Log.v("lc", "fullname=" + fullName);
Log.v("lc", "created=" + created);
Log.v("lc", "NewsImage=" + NewsImageURL);
Log.v("lc", "Meta=" + meta);
Log.v("lc", "tagline=" + tagline);
} catch
(JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public class PostTask extends AsyncTask<Void, String, Boolean> {
@Override
protected Boolean doInBackground(Void... params) {
boolean result = false;
loadNews();
publishProgress("progress");
return result;
}
protected void onProgressUpdate(String... progress) {
StringBuilder str = new StringBuilder();
for (int i = 1; i < progress.length; i++) {
str.append(progress[i] + " ");
}
}
@Override
protected void onPostExecute(Boolean result) {
super.onPostExecute(result);
Log.v("BGThread", "begin fillin data");
fillData();
}
}
public void fillData(){
NewsView = LayoutInflater.from(getBaseContext()).inflate(R.layout.newsdetailact,
null);
TextView Title = (TextView) NewsView.findViewById(R.id.NewsTitle);
Title.setText(title);
TextView Tagline = (TextView) NewsView.findViewById(R.id.subtitle);
Tagline.setText(tagline);
TextView MetaData = (TextView) NewsView.findViewById(R.id.meta);
MetaData.setText(meta);
ImageView NewsImage = (ImageView)NewsView.findViewById(R.id.imageView2);
NewsImage.setImageBitmap(bm);
TextView MainContent = (TextView) NewsView.findViewById(R.id.maintext);
MainContent.setText(content);
Log.v("BGThread", "Filled results");
adapter = new MergeAdapter();
adapter.addView(NewsView);
setListAdapter(adapter);
}
}
答案 0 :(得分:3)
请使用此代码spinet将url图像转换为位图并在图像视图中显示。
URL url = new URL("http://image10.bizrate-images.com/resize?sq=60&uid=2216744464");
Bitmap bmp = BitmapFactory.decodeStream(url.openConnection().getInputStream());
imageView.setImageBitmap(bmp);
认为它可以帮助你。
由于
答案 1 :(得分:0)
我使用Prime进行所有图像加载,轻松处理这种情况。
答案 2 :(得分:0)
String url1 = "Your URL....";
URL ulrn = new URL(url1);
HttpURLConnection con = (HttpURLConnection) ulrn
.openConnection();
InputStream is = con.getInputStream();
bmp1 = BitmapFactory.decodeStream(is);
int widthPx = 150; //you can set width
int heightPx = 150; //you can set height
bmp1=Bitmap.createScaledBitmap(bmp1, widthPx, heightPx, true);
Imgview1.setImageBitmap(bmp1);
答案 3 :(得分:0)
在这样的情况下,我会先尝试将InputStream写入文件,然后从文件加载。这通常有效。证明写入文件的另一个原因是因为我喜欢懒惰加载来自互联网的图像,因为它可能需要比预期更长的时间。在这种情况下,我怀疑InputStream在有机会完成该过程之前就已关闭。
你的代码和我的结构基本相同,没有复制到文件部分。
如果你想调查,我建议你这样做: