Question

我必须实现一个应用程序，其中我为输入PIN码和手机号码设置了小edittext。每个编辑文本一次包含1个字符。
现在，当我运行此应用程序时，我发现对于每个框，我需要将焦点放在每个edittext上。
因此，在这种情况下，可以在第一个输入字符后在下一个edittext中设置焦点，然后在第二个输入字符后转到第三个。
所以请帮我解决这个问题

这是布局图片。

enter image description here

Answer 1

1. implements TextWatcher on EditTexts

然后当你得到Edittext的文字长度是1 。

2. Change focus on other EditText using

在另一个EditText上调用requestFocus() ..

代码：（此代码仅供您理解，可能因您的情况而有所不同）

public class LoginActivity extends Activity implements TextWatcher
{
 .
 .
 .

  editTextUName = (EditText) findViewById(R.id.edttextusername);
  editTextUName.addTextChangedListener(this);
  editTextPwd = (EditText) findViewById(R.id.edttextpassword);
  editTextPwd.addTextChangedListener(this);

@Override
public void afterTextChanged(Editable s)
{
    if (s.toString().length() == 1)
    {
              editTextPwd.requestFocus();
    }
}

Answer 2

使用此代码

final EditText EditText01 = (EditText) findViewById(R.id.editText01);
final EditText EditText02= (EditText) findViewById(R.id.editText02);
final EditText EditText03 = (EditText) findViewById(R.id.editText03);
final EditText EditText04 = (EditText) findViewById(R.id.editText04);

EditText01.requestFocus();
EditText01.setOnFocusChangeListener(new View.OnFocusChangeListener() {

                    @Override
                    public void onFocusChange(final View v,
                            final boolean hasFocus) {

                        if (hasFocus) {
                            final InputMethodManager mgr = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
                            // only will trigger it if no physical keyboard is
                            // open
                            mgr.showSoftInput(EditText01,
                                    InputMethodManager.SHOW_IMPLICIT);
                        }

                    }
                });

        EditText01.setOnKeyListener(new View.OnKeyListener() {

            @Override
            public boolean onKey(final View v, final int keyCode,
                    final KeyEvent event) {

                if (event.getAction() == KeyEvent.ACTION_DOWN) {
                    if (keyCode == KeyEvent.KEYCODE_DEL) {
                        EditText01.requestFocus();
                    } else {
                        EditText02.requestFocus();
                    }
                }
                return false;
            }
        });

        EditText02.setOnKeyListener(new View.OnKeyListener() {

            @Override
            public boolean onKey(final View v, final int keyCode,
                    final KeyEvent event) {

                if (event.getAction() == KeyEvent.ACTION_DOWN) {
                    if (keyCode == KeyEvent.KEYCODE_DEL) {
                        EditText01.requestFocus();
                    } else {
                        EditText03.requestFocus();
                    }
                }
                return false;
            }
        });
        EditText03.setOnKeyListener(new View.OnKeyListener() {

            @Override
            public boolean onKey(final View v, final int keyCode,
                    final KeyEvent event) {

                if (event.getAction() == KeyEvent.ACTION_DOWN) {
                    if (keyCode == KeyEvent.KEYCODE_DEL) {
                        EditText02.requestFocus();
                    } else {
                        EditText04.requestFocus();
                    }

                }
                return false;
            }
        });

        EditText04.setOnKeyListener(new View.OnKeyListener() {

            @Override
            public boolean onKey(final View v, final int keyCode,
                    final KeyEvent event) {

                if (event.getAction() == KeyEvent.ACTION_DOWN) {
                    if (keyCode == KeyEvent.KEYCODE_DEL) {
                        EditText03.requestFocus();
                    } 

                }

                return false;

            }
        });

Answer 3

添加文本更改侦听器

      textView1.addTextChangedListener(new TextWatcher() {
            public void afterTextChanged(Editable s) {

               textView2.requestFocus();

            }

            public void beforeTextChanged(CharSequence s, int start, int count,             int after) {
             }

            public void onTextChanged(CharSequence s, int start, int before, int count) {
            }
        });

Answer 4

这应该可以正常工作。 mPinFirst等是表示每个Pin条目的EditTexts。还应该照顾退步。

    mPinFirst.setOnKeyListener(onKeyListener);
    mPinSecond.setOnKeyListener(onKeyListener);
    mPinThird.setOnKeyListener(onKeyListener);
    mPinFourth.setOnKeyListener(onKeyListener);




View.OnKeyListener onKeyListener = new View.OnKeyListener() {
        @Override
        public boolean onKey(View view, int i, KeyEvent keyEvent) {

        if(KeyEvent.KEYCODE_DEL != keyEvent.getKeyCode()) {
            if (((ESEditText) view).getText().length() == 1)
                if (view.focusSearch(View.FOCUS_RIGHT) != null) {
                    view.focusSearch(View.FOCUS_RIGHT).requestFocus();
                    return true;
                }
        }else{
            ((ESEditText) view).setText("");
            if (view.focusSearch(View.FOCUS_LEFT) != null) {
                view.focusSearch(View.FOCUS_LEFT).requestFocus();
                return true;
            }
        }
        return false;
    }
};

在第一个框中输入字符后，将焦点转到下一个框

4 个答案: