Question

查看urllib2的来源，看起来最简单的方法就是将HTTPRedirectHandler子类化，然后使用build_opener来覆盖默认的HTTPRedirectHandler，但这似乎很多（相对复杂）的工作做的似乎是它应该很简单。

Answer 1

以下是Requests方式：

import requests
r = requests.get('http://github.com', allow_redirects=False)
print(r.status_code, r.headers['Location'])

Answer 2

Dive Into Python有一个关于使用urllib2处理重定向的好章节。另一种解决方案是httplib。

>>> import httplib
>>> conn = httplib.HTTPConnection("www.bogosoft.com")
>>> conn.request("GET", "")
>>> r1 = conn.getresponse()
>>> print r1.status, r1.reason
301 Moved Permanently
>>> print r1.getheader('Location')
http://www.bogosoft.com/new/location

Answer 3

这是一个不会遵循重定向的urllib2处理程序：

class NoRedirectHandler(urllib2.HTTPRedirectHandler):
    def http_error_302(self, req, fp, code, msg, headers):
        infourl = urllib.addinfourl(fp, headers, req.get_full_url())
        infourl.status = code
        infourl.code = code
        return infourl
    http_error_300 = http_error_302
    http_error_301 = http_error_302
    http_error_303 = http_error_302
    http_error_307 = http_error_302

opener = urllib2.build_opener(NoRedirectHandler())
urllib2.install_opener(opener)

Answer 4

我想这会有所帮助

from httplib2 import Http
def get_html(uri,num_redirections=0): # put it as 0 for not to follow redirects
conn = Http()
return conn.request(uri,redirections=num_redirections)

Answer 5

redirections请求方法中的httplib2关键字是红色鲱鱼。如果收到重定向状态代码，则不会返回第一个请求，而是会引发RedirectLimit异常。要返回初始回复，您需要在follow_redirects对象上将False设置为Http：

import httplib2
h = httplib2.Http()
h.follow_redirects = False
(response, body) = h.request("http://example.com")

Answer 6

我第二次指向Dive into Python的指针。这是使用urllib2重定向处理程序的实现，比它应该做的更多工作？也许，耸耸肩。

import sys
import urllib2

class RedirectHandler(urllib2.HTTPRedirectHandler):
    def http_error_301(self, req, fp, code, msg, headers):  
        result = urllib2.HTTPRedirectHandler.http_error_301( 
            self, req, fp, code, msg, headers)              
        result.status = code                                 
        raise Exception("Permanent Redirect: %s" % 301)

    def http_error_302(self, req, fp, code, msg, headers):
        result = urllib2.HTTPRedirectHandler.http_error_302(
            self, req, fp, code, msg, headers)              
        result.status = code                                
        raise Exception("Temporary Redirect: %s" % 302)

def main(script_name, url):
   opener = urllib2.build_opener(RedirectHandler)
   urllib2.install_opener(opener)
   print urllib2.urlopen(url).read()

if __name__ == "__main__":
    main(*sys.argv)

Answer 7

最短的路是

class NoRedirect(urllib2.HTTPRedirectHandler):
    def redirect_request(self, req, fp, code, msg, hdrs, newurl):
        pass

noredir_opener = urllib2.build_opener(NoRedirect())

有没有一种简单的方法来在python中请求URL而不是遵循重定向？

7 个答案: