根据表单的选择显示/隐藏标记不起作用

时间:2012-06-13 17:49:53

标签: javascript jquery google-maps google-maps-api-3 jquery-ui-map

我试图根据用户从{{1>中选择的功能类型,在我的 Google地图上显示/隐藏(或简单地过滤)我的标记(房屋和公寓)选择框。

例如如果用户选择“游泳池”功能并点击#features按钮 - 只显示具有此功能的那些标记(住宅/公寓),以及隐藏那些没有游泳池的人。

不幸的是,当我运行代码时,我的地图上没有任何变化/变化。

房屋和公寓的

JSON (存储在 标记 变量中):

Submit

JS / jQuery 代码:

({
condos:
    [
        {Address:'123 Fake St.', Lat:'56.645654', Lng:'23.534546', features:['Swimming Pool','BBQ','..etc..']},
        {... another condo with features ...},
        {... another condo with features ...},
        ...
    ],
houses:
    [
        {Address:'1 Main Ave.', Lat:'34.765766', Lng:'27.8786674', features:['...','...']},
        {... another house with features ...},
        {... another house with features ...},
        ...
    ]
})

更新

用于在地图上创建/放置标记的

JS / jQuery 代码:

$('#filterform').on('submit', function(e) {
    e.preventDefault(); // prevent page from reloading when form is submitted

    $('#map').gmap('set', 'bounds', null); // reset map's bounds
    $('#map').gmap('closeInfoWindow'); // close opened infoWindows

    // store selected features from the 'features' select box into features variable as array
    var features = $("#features").val();

    // for each element of type house/inside houses array
    $(markers.houses).each(function(index, elem){
        //if a house has one of the selected features from 'features' select box - show it on the map, otherwise hide it
        if(jQuery.inArray(features, elem.features) !== -1 || jQuery.inArray(features, elem.features) > -1){
            this.setVisible(true);
        }else{
            this.setVisible(false);
        }
    });

    // ... repeat the same for condos type elements ...
});

2 个答案:

答案 0 :(得分:2)

$(markers.houses).each(function(index, elem){
    //if a house has one of the selected features from 'features' select box - show it on the map, otherwise hide it
    if(jQuery.inArray(features, elem.features) !== -1 || jQuery.inArray(features, elem.features) > -1){
        this.setVisible(true);
    }else{
        this.setVisible(false);
    }
});

在您的上下文中,“this”不是标记元素,它是markers.houses数组元素,与elem相同 - > this === elem

更新:使用以下行添加标记:

$('#map').gmap(mapOptions).bind('init', function(){     
    markers.housesMarkers = [];     //Adding new property that holds Markers    
    $(markers.houses).each(function(index, elem){
            var position =  new google.maps.LatLng(parseFloat(elem.lat), parseFloat(elem.lng));
            var m = new google.maps.Marker({ position:position ,
                                            icon: 'house.png' })
            //Adding markers to array
            markers.housesMarkers.push( m );
            m.setMap( $('#map').gmap('get','map') );

            $('#map').gmap('addBounds',m.getPosition());  ///'bound:true' option
    });
    markers.condosMarkers = [];      //Adding new property that holds Markers
    $(markers.condos).each(function(index, elem){
            var position =  new google.maps.LatLng(parseFloat(elem.lat), parseFloat(elem.lng));
            var m = new google.maps.Marker({ position:position ,
                                            icon: 'condo.png' })
            //Adding markers to array
            markers.condosMarkers.push( m );
            m.setMap( $('#map').gmap('get','map') );

            $('#map').gmap('addBounds',m.getPosition());  ///'bound:true' option
    });
});

然后使用以下代码'过滤'(可见/不可见)您的标记:

$(markers.houses).each(function(index, elem){
    //if a house has one of the selected features from 'features' select box - show it on the map, otherwise hide it
    if(jQuery.inArray(features, elem.features) !== -1 || jQuery.inArray(features, elem.features) > -1){
        markers.housesMarkers[index].setVisible(true);   //for condos -> 'marker.condosMarkers'
    }else{
        markers.housesMarkers[index].setVisible(false);  //for condos -> 'marker.condosMarkers'
    }
});

答案 1 :(得分:0)

试试this.setMap(null); / this.setmap(map);