我不知道我在这里做错了什么:
问。在使用共享对象编译程序时,为什么g ++找不到我的库?
我试图在我的c ++程序中包含一个共享库:
g++ -fpic -c sha.cpp
g++ -shared -o libsha.so sha.o
g++ main.cpp -o main -L. -lsha
其中sha.cpp和sha.h是库文件,main.cpp是我的程序。
我已尝试使用静态库,它可以找到:
g++ -static -c sha.cpp -o libsha.o
ar rcs libsha.a libsha.o
g++ main.cpp -o main -L. -lsha
平台是windows上的cygwin,这是输出:
rob@pc /cygdrive/c/src/a
$ g++ main.cpp -o shatest -L. -lsha
/usr/lib/gcc/i686-pc-cygwin/4.3.4/../../../../i686-pc-cygwin/bin/ld: cannot find -lsha
collect2: ld returned 1 exit status
我已阅读所有论坛帖子,但该库位于同一个文件夹中!
$ ls
libsha.so main.cpp sha.cpp sha.h sha.o
我这样做的原因是,在另一个平台上,正在创建一个库,当一个对象被调用时,它可以工作,但是当构建第二个对象时应用程序崩溃。我正在做上面的简单测试! (烦恼不是那么简单)。
以下源文件:
的main.cpp
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include "sha.h"
void *thread_one( void *ptr );
void *thread_two( void *ptr );
main()
{
pthread_t thread1, thread2;
int iret1, iret2;
/* Create independent threads each of which will execute function */
iret1 = pthread_create( &thread1, NULL, thread_one, 0);
iret2 = pthread_create( &thread2, NULL, thread_two, 0);
/* Wait till threads are complete before main continues. Unless we */
/* wait we run the risk of executing an exit which will terminate */
/* the process and all threads before the threads have completed. */
pthread_join( thread1, NULL);
pthread_join( thread2, NULL);
printf("Thread 1 returns: %d\n",iret1);
printf("Thread 2 returns: %d\n",iret2);
exit(0);
}
void *thread_one( void *ptr )
{
printf("Run thread_one\n");
CObj1 obj;
}
void *thread_two( void *ptr )
{
printf("Run thread_two\n");
CObj2 obj;
}
sha.cpp
#include <stdio.h>
#include <stdlib.h>
#include "sha.h"
CObj1::CObj1()
{
printf("CObj1\n");
a = 10;
printf("CObj1: %d \n", a);
}
CObj2::CObj2()
{
printf("CObj2\n");
a = 10;
printf("CObj2: %d \n", a);
}
sha.h
#ifndef LIB
#define LIB
class CObj1
{
public:
CObj1();
private:
int a;
};
class CObj2
{
public:
CObj2();
private:
int a;
};
#endif