在下面的代码中,抛出了两种情况的异常,如main()所示。
#include <iostream>
// Our own exception classes - just for fun.
class myExceptionClassA
{
public:
myExceptionClassA () {std::cout << "\nWarning: Division by zero isn't allowed.\n";}
};
class myExceptionClassB
{
public:
myExceptionClassB () {std::cout << "\nWarning: Division by dividend isn't allowed.\n";}
};
class divisionClass
{
private:
int *result;
public:
divisionClass ()
{
// Allocating memory to the private variable.
result = new int;
}
/*
The class function `doDivide`:
1. Throws above defined exceptions on the specified cases.
2. Returns the division result.
*/
int doDivide (int toBeDividedBy) throw (myExceptionClassA, myExceptionClassB)
{
*result = 200000;
// If the divisor is 0, then throw an exception.
if (toBeDividedBy == 0)
{
throw myExceptionClassA ();
}
// If the divisor is same as dividend, then throw an exception.
else if (toBeDividedBy == *result)
{
throw myExceptionClassB ();
}
// The following code won't get executed if/when an exception is thrown.
std :: cout <<"\nException wasn't thrown. :)";
*result = *result / toBeDividedBy;
return *result;
}
~divisionClass ()
{
std::cout << "\ndddddddddd\n";
delete result;
}
};
int main ()
{
divisionClass obj;
try
{
obj.doDivide (200000);
}
catch (myExceptionClassA) {}
catch (myExceptionClassB) {}
try
{
obj.doDivide (3);
}
catch (myExceptionClassA) {}
catch (myExceptionClassB) {}
try
{
obj.doDivide (0);
}
catch (myExceptionClassA) {}
catch (myExceptionClassB) {}
try
{
obj.doDivide (4);
}
catch (myExceptionClassA) {}
catch (myExceptionClassB) {}
return 0;
}
- 打印两个异常类打印语句 - 析构函数中的语句只打印一次 - Valgrind没有显示任何内存泄漏。
anisha@linux-y3pi:~/Desktop> g++ exceptionSafe3.cpp -Wall
anisha@linux-y3pi:~/Desktop> valgrind ./a.out
==18838== Memcheck, a memory error detector
==18838== Copyright (C) 2002-2009, and GNU GPL'd, by Julian Seward et al.
==18838== Using Valgrind-3.5.0 and LibVEX; rerun with -h for copyright info
==18838== Command: ./a.out
==18838==
Warning: Division by dividend isn't allowed.
Exception wasn't thrown. :)
Warning: Division by zero isn't allowed.
Exception wasn't thrown. :)
dddddddddd
==18838==
==18838== HEAP SUMMARY:
==18838== in use at exit: 0 bytes in 0 blocks
==18838== total heap usage: 3 allocs, 3 frees, 262 bytes allocated
==18838==
==18838== All heap blocks were freed -- no leaks are possible
==18838==
==18838== For counts of detected and suppressed errors, rerun with: -v
==18838== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 2 from 2)
anisha@linux-y3pi:~/Desktop>
析构函数不应该被调用3次 - 例外两次,返回语句一次吗?
请解释我失踪的一点。
现在我通过删除main()中的所有try catch块来尝试它 析构函数根本没有被调用?
anisha@linux-y3pi:~/Desktop> valgrind ./a.out
==18994== Memcheck, a memory error detector
==18994== Copyright (C) 2002-2009, and GNU GPL'd, by Julian Seward et al.
==18994== Using Valgrind-3.5.0 and LibVEX; rerun with -h for copyright info
==18994== Command: ./a.out
==18994==
Warning: Division by dividend isn't allowed.
terminate called after throwing an instance of 'myExceptionClassB'
==18994==
==18994== HEAP SUMMARY:
==18994== in use at exit: 133 bytes in 2 blocks
==18994== total heap usage: 3 allocs, 1 frees, 165 bytes allocated
==18994==
==18994== LEAK SUMMARY:
==18994== definitely lost: 0 bytes in 0 blocks
==18994== indirectly lost: 0 bytes in 0 blocks
==18994== possibly lost: 129 bytes in 1 blocks
==18994== still reachable: 4 bytes in 1 blocks
==18994== suppressed: 0 bytes in 0 blocks
==18994== Rerun with --leak-check=full to see details of leaked memory
==18994==
==18994== For counts of detected and suppressed errors, rerun with: -v
==18994== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 2 from 2)
Aborted
anisha@linux-y3pi:~/Desktop>
答案 0 :(得分:3)
从方法中抛出异常不会破坏拥有它的对象。只有当它被删除或超出范围(在这种情况下,在main()的末尾)时才会被销毁并且析构函数被调用。
答案 1 :(得分:3)
当您捕获异常时,堆栈在抛出异常的点与捕获异常的点之间“展开”。这意味着这两个点之间范围内的所有自动变量都将被销毁 - try
内与catch
对应的所有内容都匹配异常。
您的对象obj
是main
函数中try
以外的自动变量。因此,当堆栈展开时它不会被破坏。您的代码依赖于这一事实 - 在第一次catch
之后再次调用doDivide
,因此最好不要将其销毁。
如果你根本没有捕获异常,那么在程序终止之前,无论堆栈是否被展开(在C ++ 11中为15.3 / 9),它都是实现定义的。它看起来好像在你的第二次测试中,没有任何catch
条款,它不是。
这意味着如果您希望RAII对象“正常工作”,那么您不能在程序中允许未捕获的异常。你可以这样做:
int main() {
try {
do_all_the_work();
} catch (...) {
throw; // or just exit
}
}
现在可以保证,如果异常转义函数,do_all_the_work
中的任何自动变量都将被销毁。缺点是你可能会从调试器中获得更少的信息,因为它已经忘记了未被捕获的异常的原始throw网站。
当然,程序中的代码仍有可能阻止您的obj
被破坏,例如通过调用abort()
。
答案 2 :(得分:2)
消息打印在divisionClass
的析构函数中。您只有一个该类型的对象,它会在main
结束时被销毁。
答案 3 :(得分:0)
当抛出异常时,在调用堆栈的某处有一个匹配的catch
处理程序时,保证会发生堆栈展开。您可以像这样简化和可视化堆栈:
+-------------------+
| locals | obj.doDivide()
+-------------------+
| | try {}
+-------------------+
| catch { } |
| | main()
| DivisionClass obj |
+-------------------+
只有堆栈中的部分(在上面的图片中)被解开并且相应的对象被破坏。带有divisonClass对象的堆栈部分保持不变,直到main()退出。
试试这段代码,看看差异:
void foo()
{
divisionClass obj;
obj.doDivide(0);
}
int main()
{
try {
foo();
}
catch (myExceptionClassA) {
std::cout << "Check point.\n";
}
}