我的2个相关下拉列表exam_type和状态工作正常,它们显示值..但这些值没有设置成数据库..plz帮助我...这是我的代码
表单视图:
<tr>
<td><?php echo $form->labelEx($model,'exam type :'); ?></td>
<td>
<?php echo CHtml::dropDownList('exam_type','',CHtml::listData(class1::model()->findAll(),'class','class'),array('empty'=>'Choose one',
'ajax' => array(
'type'=>'POST', //request type
'url'=>CController::createUrl('dynamicstates'), //url to call.
//Style: CController::createUrl('currentController/methodToCall')
'update'=>'#status', //selector to update
)));
//empty since it will be filled by the other dropdown
?>
</td>
<td> <?php echo $form->error($model,'exam_type'); ?></td>
</tr>
<tr>
<td><?php echo $form->labelEx($model,'status :'); ?></td>
<td><?php echo CHtml::dropDownList('status','', array());?></td>
<td> <?php echo $form->error($model,'status'); ?></td>
</tr>
public function actiondynamicstates()
{
echo $aasd=$_POST['exam_type'];
echo $data=admission::model()->findAll('class=:class',
array(':class'=>$aasd));
$data=CHtml::listData($data,'studentid','studentfname');
foreach($data as $value=>$name)
echo CHtml::tag('option', array('value'=>$value), CHtml::encode($name), true);
}
答案 0 :(得分:1)
很可能是下拉列表中的问题。你应该替换
CHtml::dropDownList('exam_type'
与
CHtml::dropDownList(CHtml::activeName($model, 'exam_type'
和
CHtml::dropDownList('status'
与
CHtml::dropDownList(CHtml::activeName($model, 'status'
答案 1 :(得分:1)
在我遇到这个问题之前几天。我做了一些工作。
<tr>
<td><?php echo $form->labelEx($model,'exam type :'); ?></td>
<td>
<?php echo CHtml::dropDownList('exam_type','',CHtml::listData(class1::model()->findAll(),'class','class'),array('empty'=>'Choose one',
'ajax' => array(
'type'=>'POST', //request type
'url'=>CController::createUrl('dynamicstates'), //url to call.
//Style: CController::createUrl('currentController/methodToCall')
// 'update'=>'#status', //selector to update
'update'=>'#modelname_status', //here is the trick replace modelname to orginal model class name
)));
//empty since it will be filled by the other dropdown
?>
</td>
<td> <?php echo $form->error($model,'exam_type'); ?></td>
</tr>
<tr>
<td><?php echo $form->labelEx($model,'status :'); ?></td>
<?php //echo CHtml::dropDownList('status','', array());?>
<td><?php echo CHtml::dropDownList('modelname[status]','', array());?></td>//same here
<td> <?php echo $form->error($model,'status'); ?></td>
</tr>
在上面的代码中我改变了:
'update'=>'#modelname_status', //here is the trick replace modelname to orginal model class name
<td><?php echo CHtml::dropDownList('modelname[status]','', array());?></td>//same here
即使它没有工作给予评论。(我没有测试,也许你的控制器似乎有问题。)
答案 2 :(得分:0)
我希望你的问题已经解决了。如果有人仍然想知道为什么这些下拉列表不更新数据库,则不会因为它们未被列为安全属性。 下面是一个使下拉列表工作的示例(仅给出重要部分):
假设您要添加名为“showOnHome”的字段。首先,在数据库表中创建一个名为“showOnHome”的字段(我更喜欢int(1)作为字段类型)。
然后,在您的模型中:
public function rules() {
....
....
array('showOnHome','safe'),
}
....
....
public function attributeLabels() {
return array(
.....
.....
.....
'showOnHome' => 'Show On Homepage' ,
)
}
在您的视图中
<div class="row">
<?php echo $form->labelEx($model,'showOnHome'); ?>
<?php echo $form->dropDownList($model, 'showOnHome', array('0'=>'No','1'=>'Yes') , array('empty'=>'--Select--')); ?>
<?php echo $form->error($model,'showOnHome'); ?>
</div>
如果你没有改变Yii生成的默认控制器代码,上面的代码snippsets应该可以完成你的工作,例如
/**
* Creates a new model.
* If creation is successful, the browser will be redirected to the 'view' page.
*/
public function actionCreate()
{
$model=new Livefuture;
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['Livefuture']))
{
$model->attributes=$_POST['Livefuture'];
if($model->save())
$this->redirect(array('view','id'=>$model->id));
}
$this->render('create',array(
'model'=>$model,
));
}
/**
* Updates a particular model.
* If update is successful, the browser will be redirected to the 'view' page.
* @param integer $id the ID of the model to be updated
*/
public function actionUpdate($id)
{
$model=$this->loadModel($id);
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['Livefuture']))
{
$model->attributes=$_POST['Livefuture'];
if($model->save())
$this->redirect(array('view','id'=>$model->id));
}
$this->render('update',array(
'model'=>$model,
));
}