//viewdidload
{
str1 = [[NSMutableString alloc] initWithCapacity:0];
str2 = [[NSMutableString alloc] initWithCapacity:0];
}//
for (int pq=1; pq<=temp; pq++)
{
str1 = [NSMutableString stringWithString:[documentManager wholeTextForPage:pq] ] ;
[self.str2 appendString:str1];
NSLog(@"content of page chumma1: %@",str1);
}
NSLog(@"cwhole text: %@",str2
**这里str1在每次迭代时返回不同的字符串。我试图将str1返回的每个字符串附加到str2。但str2在第一次迭代时只返回str1返回的一个字符串。其他迭代返回的字符串不会附加到str2。请帮助我找到一种方法来解决这个问题。提前致谢。
谢谢&amp;问候 VEERA **
答案 0 :(得分:0)
Use stringByAppendingString see example:
But str2 should declare NSString
<强>更新强>
NSMutableString *str1 = [NSMutableString string];
NSString *str2 = @"";
for (int pq=1; pq<=temp; pq++)
{
str1 = [NSMutableString stringWithString:[documentManager wholeTextForPage:pq] ] ;
str2 = [str2 stringByAppendingString:str1];
}
这会将所有数据从str1追加到str2。
答案 1 :(得分:0)
尝试这样的事情......
....
for (int pq=0; pq < temp; pq++) {
str1 = [NSMutableString stringWithString:[documentManager wholeTextForPage:pq] ] ;
[self.str2 appendString:str1];
NSLog(@"content of page chumma1: %@",str1);
}
NSLog(@"cwhole text: %@",str2
答案 2 :(得分:0)
这样做是为了追加字符串:
str1 = [[NSMutableString alloc] initWithCapacity:0];
for (int pq=1; pq<=temp; pq++)
{
str1 = [str1 stringByAppendingString:[NSString stringWithString:[documentManager wholeTextForPage:pq]]];
}
答案 3 :(得分:0)
NSMutableString *str1= [NSMutableString new];
for (int i =0; i < 10; i++) {
[str1 appendString:@"Hi "];
}
NSLog(@"%@",str1);
您的代码可能无效,因为appendString:(NSString *)str不是NSMutableString。所以使用NSString。
代码试试这个
for (int pq=1; pq<=temp; pq++)
[self.str2 appendString:[documentManager wholeTextForPage:pq]];
答案 4 :(得分:0)
以这种方式尝试......
NSMutableString *str1 = [[NSMutableString alloc]initWithCapacity:0];
NSMutableString *str2 = [[NSMutableString alloc]initWithCapacity:0];
for(int pq=1; pq<temp; pq++)
{
str1 = [NSMutableString stringWithFormat:[documentManager wholeTextForPage:pq]];
str2 = (NSMutableString *)[str2 stringByAppendingFormat:str1];
NSLog(@"content of page chumma1: %@",str1);
}
NSLog(@"cwhole text: %@",str2);