这是this question from yesterday的延续。
以下是我的三个表:
战士表
fighter_id | name
-----------------------
1 | John
2 | Steve
3 | Bill
4 | Bobby
活动表
event_id | event_name | event_date
-------------------------------------------
1 | MMA | 01/01/2010
2 | Cool | 02/20/2010
3 | Yeaa! | 04/15/2010
战斗表
fight_id | fighter_a | fighter_b | winner | method | event
-----------------------------------------------------------------------
1 | 1 | 2 | 1 | Sub | 1
2 | 4 | 1 | 4 | KO | 2
3 | 1 | 3 | NULL | Draw | 3
试图获得结果
result | opponent | method | event | date
----------------------------------------------------------
Draw | Bill | Draw | Yeaa! | 04/15/2010
Loss | Bobby | KO | Cool | 02/20/2010
Win | Steve | Sub | MMA | 01/01/2010
因此在战斗表中,fighter_a,fighter_b和winner是与Fighters表中的fighter_id相对应的整数。
我基本上是在基于fighter_id($ fighter_id)检索数据的页面上。
我正在尝试用该战斗机的每次战斗创建行,包括他的对手的名字,结果(胜利,失败,平局或者nc),方法,event_name和event_date。挑战在于胜利者可以是战士_或战士。它并不总是在同一列中。我感谢任何帮助。
select
fight_id,
CASE
WHEN winner is not null and winner=fighter_id then 'win'
WHEN winner is not null and winner<>fighter_id then 'loss'
WHEN winner is null and method='Draw' then 'draw'
WHEN winner is null and method = 'No Contest' then 'no contest'
ELSE ''
END as match_result,
participant.name 'participant',
opponent.name 'opponent'
FROM fights
INNER JOIN fighters as participant on participant.fighter_id = fights.fighter_a
INNER JOIN fighters as oppoent on opponent.fighter_id = fights.fighter_b
WHERE
fighter_a=$fighter_id OR fighter_b=$fighter_id
ORDER BY
event_date DESC
答案 0 :(得分:1)
您只需修改CASE
个语句即可与$fighter_id
匹配。
所以你的CASE
陈述会是 -
select fight_id,
CASE
WHEN winner is not null and winner = f.fighter_id then 'win'
WHEN winner is not null and winner <> f.fighter_id then 'loss'
WHEN winner is null and method='Draw' then 'draw'
WHEN winner is null and method = 'No Contest' then 'no contest'
ELSE ''
END as match_result,
f.name AS participant,
(SELECT o.name FROM fighters o WHERE o.fighter_id = IF(f.fighter_id = fs.fighter_a, fs.fighter_b, fs.fighter_a)) AS opponent
FROM fights fs,
fighters f
WHERE f.fighter_id = $fighter_id
AND (fs.fighter_a = f.fighter_id OR fs.fighter_b = f.fighter_id)
答案 1 :(得分:1)
你可以使用联盟:
SELECT CASE WHEN winner = participant_id THEN 'Win'
WHEN winner = opponent_id then 'Loss'
ELSE method
END AS result, fighters.name AS opponent, method, event_name, event_date
FROM fights
INNER JOIN fighters ON fighter_id = opponent_id
INNER JOIN events ON event = event_id
WHERE participant_id = $fighter_id
UNION ALL
SELECT CASE WHEN winner = participant_id THEN 'Loss'
WHEN winner = opponent_id then 'Win'
ELSE method
END AS result, fighters.name AS opponent, method, event_name, event_date
FROM fights
INNER JOIN fighters ON fighter_id = participant_id
INNER JOIN events ON event = event_id
WHERE opponent_id = $fighter_id
ORDER BY event_date DESC
答案 2 :(得分:1)
使用带有条件的subselect将你要查找的fighter_id切换到column_a(如果它在column_b中),这样就简化了操作并加入了外部查询:
SELECT
(
CASE
WHEN a.winner = a.f_a THEN 'Win'
WHEN a.winner = a.f_b THEN 'Loss'
WHEN a.winner IS NULL THEN a.method
END
) AS result,
b.name AS opponent,
a.method AS method,
c.event_name AS event,
c.event_date AS date
FROM
(
SELECT
IF(fighter_b = $fighter_id, fighter_b, fighter_a) AS f_a,
IF(fighter_b = $fighter_id, fighter_a, fighter_b) AS f_b,
winner,
method,
event
FROM
fights
WHERE
$fighter_id IN (fighter_a, fighter_b)
) a
INNER JOIN
fighters b ON a.f_b = b.fighter_id
INNER JOIN
events c ON a.event = c.event_id
ORDER BY
c.event_date DESC
此外,如果获胜者字段为空,则只需回显方法字段。这样,当您想要添加另一种类型的方法,其中wins对您的系统为null时,您不必继续对CASE
语句进行更多条件检查。
答案 3 :(得分:0)
SELECT
CASE
WHEN winner is not null and winner=fighter_id then 'win'
WHEN winner is not null and winner<>fighter_id then 'loss'
WHEN winner is null and method='Draw' then 'draw'
WHEN winner is null and method = 'No Contest' then 'no contest'
ELSE ''
END result,
f2.name opponent,
method,
event_name event,
event_date date
FROM fights f1
INNER JOIN fighters f2
ON f1.fighter_b = f2.fighter_id
INNER JOIN events e
ON e.event_id = f1.event
ORDER BY date DESC