Question

我正在尝试将.xml文件从res文件夹传递到XMLReader，以便将其解析为对象：

private void parseXML() {
    String parsedData = "";
       try {
           Log.w("AndroidParseXMLActivity", "Start");
           /** Handling XML */
           SAXParserFactory spf = SAXParserFactory.newInstance();
           SAXParser sp = spf.newSAXParser();
           XMLReader xr = sp.getXMLReader();

           QuestionXMLHandler myXMLHandler = new QuestionXMLHandler();
           xr.setContentHandler(myXMLHandler);
           InputSource inStream = new InputSource();
           Log.w("AndroidParseXMLActivity", "Parse1");

           inStream.setCharacterStream(new StringReader(getResources().getXml(R.xml.questions).toString()));
           Log.w("AndroidParseXMLActivity", "Parse2");

           xr.parse(inStream);
           Log.w("AndroidParseXMLActivity", "Parse3");

           ArrayList<QuestionMaster> questionList = myXMLHandler.getQuestionsList();
           for(int i=0;i<questionList.size();i++){
                QuestionMaster question = questionList.get(i);
                parsedData = parsedData + "----->\n";
                parsedData = parsedData + "Queston No: " + question.getQuestionNo() + "\n";
                parsedData = parsedData + "QuestionText: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "CorrectAnswer: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "WrongAnswer1: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "WrongAnswer2: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "WrongAnswer3: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "Answered: " + question.isAnswered() + "\n";
                parsedData = parsedData + "QuestionText: " + question.isAnsweredCorrectly() + "\n";
            }
            Log.w("AndroidParseXMLActivity", "Done");
        }catch (Exception e) {
            Log.w("AndroidParseXMLActivity",e );
        }
        xmlOutput.setText(parsedData);
    }
}

我确信这就是行：

inStream.setCharacterStream(new StringReader(getResources().getXml(R.xml.questions).toString()));

有人可以指导我将此 .xml文件传递给XMLReader 。

修改：

将其更改为：

InputSource inStream = new InputSource(getResources().openRawResource(R.raw.questions));

Answer 1

InputStream inStream = getResources().openRawResource(R.raw.questions);
xr.parse(inStream);

Answer 2

getXml()会返回XmlPullParser的实现，因此它已设置为parsed using that engine。将现有代码更改为使用XmlPullParser而不是SAX。

Answer 3

我认为您应该将文件放在raw或asset文件夹中以使用SAX解析器，然后使用上下文从那里读取该文件

Android - 从资产中读取文件 http://www.javacodegeeks.com/2012/02/android-read-file-from-assets.html

将XML资源传递给XMLReader

3 个答案: