在iOS 5上,我正在尝试使用动态主题标签搜索术语打开本机Twitter应用。
我试过了:
- (void)openForHashTag:(NSString *)hashTag {
UIApplication *app = [UIApplication sharedApplication];
NSURL *twitterURL = [NSURL URLWithString:[NSString stringWithFormat:@"twitter://search?q=%@", hashTag]];
DLog(@"Hashtag URL: %@ ", twitterURL);
if ([app canOpenURL:twitterURL]) {
[app openURL:twitterURL];
}
else {
NSURL *safariURL = [NSURL URLWithString:[NSString stringWithFormat:@"http://mobile.twitter.com/search?q=%@", hashTag]];
[app openURL:safariURL];
}
}
它似乎转到了主题标签搜索页面,但是会花费永远加载... twitter://search?q=%@
格式是否错误?
答案 0 :(得分:3)
- (void)openForHashTag:(NSString *)hashTag {
UIApplication *app = [UIApplication sharedApplication];
// NOTE: you must percent escape the query (# becomes %23)
NSString *cleanQuery = [hashTag stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *twitterURL = [NSURL URLWithString:[NSString stringWithFormat:@"twitter://search?query=%@", cleanQuery]];
if ([app canOpenURL:twitterURL]) {
[app openURL:twitterURL];
} else {
NSURL *safariURL = [NSURL URLWithString:[NSString stringWithFormat:@"http://mobile.twitter.com/search?q=%@", cleanQuery]];
[app openURL:safariURL];
}
}
答案 1 :(得分:2)
打开Twitter应用并搜索主题标签的正确网址是
twitter://search?query=hashtag
答案 2 :(得分:1)
好吧,经过大量的讨论,我意识到散列标记的搜索查询不应包含实际的散列标记...因此通过添加行
NSString *cleanString = [hashTag stringByReplacingOccurrencesOfString:@"#" withString:@""];
它现在工作正常......神秘解决了。
答案 3 :(得分:0)
更新上述代码的快速版本
private func openTwitterHashTag() {
// self.viewModel.programInfo.twitterHash = "#tag"
guard let hashTagQuery = self.viewModel.programInfo.twitterHash.addingPercentEncoding(
withAllowedCharacters: .urlHostAllowed
) else { return }
// CASE: OPEN IN NATIVE TWITTER APP
if let twitterUrl = URL(string: "twitter://search?query=\(hashTagQuery)"),
UIApplication.shared.canOpenURL(twitterUrl) {
UIApplication.shared.open(twitterUrl, options: [:], completionHandler: nil)
return
}
// CASE: OPEN ON SAFARI VIEW CONTROLLER
if let twitterWebUrl = URL(string: "http://mobile.twitter.com/search?q=\(hashTagQuery)") {
let svc = SFSafariViewController.init(url: twitterWebUrl)
self.present(svc, animated: true, completion: nil)
}
}
还可以在 info.plist
中添加权限<key>LSApplicationQueriesSchemes</key>
<array>
<string>twitter</string>
</array>