SQL查询(执行计划成本= 0.0127553)
SELECT
SUM(DATEDIFF(second, DTActivate, DTDeActivate)) AS Seconds,
AA.ID AS AAID,
AA.WorkStation
FROM
DbLogItems I
INNER JOIN DbApplicationArguments AA ON
AA.Id = I.ApplicationArgument_ID
GROUP BY
AA.ID,
AA.WorkStation
C#
var q = from items in db.LogItem
join aa in db.ApplicationArguments on
items.ApplicationArgument.ID equals aa.ID
into aaGroup
from aaJoin in aaGroup.DefaultIfEmpty()
group items by new
{
aaJoin.ID,
aaJoin.WorkStation
} into grouping
select new
{
Seconds = grouping.Sum(x => SqlFunctions.DateDiff("second", x.DTActivate, x.DTDeActivate)),
grouping.Key.ID,
grouping.Key.WorkStation
};
结果SQL非常大(执行计划成本= 0.0199849)
SELECT
1 AS [C1],
[GroupBy1].[A1] AS [C2],
[GroupBy1].[K1] AS [ID],
[GroupBy1].[K2] AS [WorkStation]
FROM
(
SELECT
[Join1].[K1] AS [K1],
[Join1].[K2] AS [K2],
SUM([Join1].[A1]) AS [A1]
FROM
(
SELECT
[Extent2].[ID] AS [K1],
[Extent2].[WorkStation] AS [K2],
DATEDIFF(second, [Extent1].[DTActivate], [Extent1].[DTDeActivate]) AS [A1]
FROM
[dbo].[DbLogItems] AS [Extent1]
LEFT OUTER JOIN [dbo].[DbApplicationArguments] AS [Extent2]
ON [Extent1].[ApplicationArgument_ID] = [Extent2].[ID]
) AS [Join1]
GROUP BY
[K1],
[K2]
) AS [GroupBy1]
帮助请写正确的linq代码 我的SQL执行计划成本= 0.0127553 Linq SQL执行计划成本= 0.0199849 DIFF = 0,0072296 21 + 10条记录
答案 0 :(得分:1)
LINQ to SQL查询就是这样。有时你不能发出更好的SQL。但是,您可以编写普通的旧T-SQL并以多种方式调用它:一个表值UDF,可能是您自定义的DataContext
公开为IQueryable
。