我正在使用Caliburn Micro和WPF。我想在左侧创建一个带有菜单的应用程序,并在应用程序的右侧创建一个网格。单击菜单项时,右侧的网格将更改为另一个视图。另一个视图将在一个单独的文件中。
MainWindowView:
<UserControl x:Class="CMDemo.Views.MainWindowView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="90*" />
<ColumnDefinition Width="210*" />
</Grid.ColumnDefinitions>
<StackPanel Name="LeftMenu">
<Button Name="ChangeDisplay" Content="Click Me"></Button>
<TextBlock x:Name="MyString"></TextBlock>
</StackPanel>
<Grid Grid.Column="1" x:Name="MainGridContent" />
</Grid>
MainWindowViewModel:
public class MainWindowViewModel : PropertyChangedBase
{
private UserControl mainGridContent;
private string myString;
public UserControl MainGridContent
{
get { return this.mainGridContent; }
set
{
this.mainGridContent = value;
NotifyOfPropertyChange(() => this.MainGridContent);
}
}
public string MyString
{
get { return this.myString; }
set
{
this.myString = value;
NotifyOfPropertyChange(() => this.MyString);
}
}
public void ChangeDisplay()
{
this.MainGridContent = new ChangeDisplayView();
this.MyString = "Testing....";
}
}
changeDisplayViewModel:
public class changeDisplayViewModel: PropertyChangedBase
{
}
changeDisplayView:
<UserControl x:Class="CMDemo.Views.changeDisplayView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<Grid>
<TextBox content="Hello Caliburn Micro">
</Grid>
当我单击“单击我”按钮时,TextBlock“MyString”会更新并显示,但用户控件不会。我做错了什么?
答案 0 :(得分:1)
尝试将MainGridContent更改为changeDisplayViewModel而不是视图本身。