我需要帮助才能使用过滤器工具栏下拉列表对jqgrid数据进行范围选择 - 我检查了它只有的sopt选项 -
['equal','not equal', 'less', 'less or equal','greater','greater or equal', 'begins with','does not begin with','is in','is not in','ends with','does not end with','contains','does not contain']
我无法在工具栏上找到关于如何使用此范围的任何线索。我的过滤器工具栏上有一个类似"All", "1-4", "5-9"
的值的下拉列表,当我选择说'1-4'
时,我希望网格填充属于该范围的所有行。我查看了一堆来自stackoverflow和trirand本身的过滤器示例,但它们似乎都是针对搜索框的。
我很感激有任何帮助来实现这一目标,谢谢。
答案 0 :(得分:0)
我能够根据样本多字样本 - http://www.ok-soft-gmbh.com/jqGrid/MultiwordSearchingToolbar.htm按范围实现此过滤器。大多数代码来自上面提到的样本,只有很小的改动。根据Oleg的反馈进行修改,使其成为le和ge。
modifySearchingFilter = function (separator) {
var i, rules, rule, parts, group, str;
var filters = $.parseJSON(this.p.postData.filters);
if(separator != '-')
return;
if (filters && typeof filters.rules !== 'undefined' && filters.rules.length > 0) {
rules = filters.rules;
for (i = 0; i < rules.length; i++) {
rule = rules[i];
if (rule.op === 'range') {
// Range should only have 2 parts lowerbound and upperbound
parts = rule.data.split(separator);
if (parts.length == 2) {
if (typeof filters.groups === 'undefined') {
filters.groups = [];
}
group = {
groupOp: 'AND',
groups: [],
rules: []
};
filters.groups.push(group);
// Breaking to 2 rules one le and other ge
group.rules.push({
data: (parts[0]),
op: "ge",
field: rule.field
});
group.rules.push({
data: (parts[1]),
op: "le",
field: rule.field
});
rules.splice(i, 1);
i--; // to skip i++
}
}
}
this.p.postData.filters = JSON.stringify(filters);
}
},
//using range op so that it is not confused with other ops
setRangeSearchSelect = function(columnName) {
grid.jqGrid('setColProp', columnName,
{
stype: 'select',
searchoptions: { value:buildRangeSearchSelect(),
sopt:['range'],
}
});
};
grid.jqGrid('filterToolbar',
{
stringResult:true,
searchOnEnter:true,
defaultSearch:"cn",
beforeSearch: function () {
modifySearchingFilter.call(this, '-');
}});