如何让googlebot查看ajax内容

时间:2012-06-09 23:28:59

标签: ajax post googlebot

我能以某种方式轻松获取googlebot以查看此ajax内容吗?使用post ajax方法:

致电页面:

<html>
<head>
<title>TEST</title>
</head>
<body onload="getTest(1)">
<div id="txtHint"></div>        
<script type="text/javascript">
function getTest(page)
{
    var parameters = "";
    document.getElementById("txtHint").innerHTML="";
    if (window.XMLHttpRequest)
    {// code for IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp=new XMLHttpRequest();
    }
    else
    {// code for IE6, IE5
        xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
    }
    xmlhttp.onreadystatechange=function()
    {
        if (xmlhttp.readyState==4 && xmlhttp.status==200)
        {
            document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
        }
    }
    parameters = parameters + "page="+page;
    xmlhttp.open("POST","ajaxtest.php",true);
    xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
    xmlhttp.send(parameters);
}
</script>
</body>
</html>

ajaxtest.php:

<?php
    $page=$_POST["page"];
    echo "This is page number $page <br />";
    echo "<a href='javascript:getTest(2);'>Link to page 2</a>"; 
?>

这正是我想要的,它的工作原理。导航在ajax调用中生成。唯一的问题是Google无法看到它......

2 个答案:

答案 0 :(得分:0)

Google explains exactly how to do it。仅供参考,通常使用Ajax或JavaScript来生成内容a really bad idea

答案 1 :(得分:0)

<div id="txtHint"><?php include 'ajaxtest.php'; ?></div> 

无法解决您的问题?