Question

我有2个个人资料模型。我正在创建一个“参加者”对象。如何在两个配置文件之间进行过滤？

class Profile1(models.Model):
    user = models.ForeignKey(User, null=True, unique=True)

class Profile2(models.Model):
    user = models.ForeignKey(User, null=True, unique=True)

class Attendee(models.Model):
    event = models.ForeignKey(Event)
    # This filters through everything... How do I filter down just to the 2 profile objects?
    content_type = models.ForeignKey(ContentType)
    object_id = models.PositiveIntegerField()
    profile = generic.GenericForeignKey('content_type', 'object_id')

感谢您的帮助！

Answer 1

由于ContentType model有三个字段app_label，model和name。因此，您可以轻松过滤这些字段。

attendees = Attendee.objects.filter(content_type__model = 'Profile1')

Answer 2

我会去

from django.contrib.contenttypes.models import ContentType
...

Attendee.objects.filter(
   content_type=ContentType.objects.get_for_model(Profile1))

避免在重构类名后比较字符串和错误。

在Django中使用ContentType过滤2个模型

2 个答案: